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3 years ago

I only need help with the last one the circle one to be pacific. I need help by tonight so I can get this done.

Mathematics

1 answer:

Degger [83]3 years ago

6 0

Answer:

$V = 997.8 {cm}^{3}$

Step-by-step explanation:

The last one is spherical

The volume of a sphere is given by:

$V= \frac{4}{3} \pi \: {r}^{3}$

From the diagram, the the radius is r=6.2 cm.

We substitute to get:

$V= \frac{4}{3} \times 3.14\: \times {6.2}^{3}$

This evaluate to;

$V = 997.8 {cm}^{3}$

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How to solve for first derivative?? I have two questions, one where I have the answer, however one where I don’t. The format of

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Answer:

Q1: $f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)$

Q2: $f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)$

Step-by-step explanation:

The derivative of the product of two functions is:

$f(x) = v(x)u(x)$

$f'(x) = v(x)u'(x) + u(x)v'x)$

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

$f(x) = 6x^8(-6x^8 + 2x^4 + 4)$

You can think of that function as the product of functions

$u(x) = 6x^8$ and $v(x) = -6x^8 + 2x^4 + 4$

We first find the derivatives of functions u and v:

$u'(x) = 48x^7$ and $v'(x) = -48x^7 + 8x^3$

Now we follow the rule above:

$f'(x) = v(x)u'(x) + u(x)v'x)$

$f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)$

Use the commutative property to change the order of the sum.

$f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)$

This is the solution you have.

Q2: The function you are given is:

$f(x) = 6x^4(6x^3 - 6x^9 + 3)$

You can think of that function as the product of functions

$u(x) = 6x^4$ and $v(x) = 6x^3 - 6x^9 + 3$

We first find the derivatives of functions u and v:

$u'(x) = 24x^3$ and $v'(x) = 18x^2 - 54x^8$

Now we follow the rule above:

$f'(x) = v(x)u'(x) + u(x)v'x)$

$f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)$

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3 years ago

Q6) Renee buys 5kg of sweets to sell. She pays £10 for the sweets. Renee puts all the sweets into bags. She puts 250g of sweets

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Answer:

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Step-by-step explanation:

100 pence in a pound.

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She bought 5000g of sweets.

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She put them into 5000÷250=20 bags.

She sells the bags for 65 pence each.

She sells them all for 20×65=1300 pence.

She gets a profit of 300 pence or 3 pounds.

She gets a percent profit of 30%.

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