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balandron [24]
3 years ago
13

3. Determine the bulk temperature, center line temperature, and surface temperature for a laminar flow in a 2 cm inner diameter

tube with defined velocity and temperature profiles: a. u=0.1[1-(r/0.01)^2] m/s b. T=400-3x10^6(1.875x10^-5-0.25r^2+624r^4) K c. Calculate the heat flux at the wall and the Nusselt number if the fluid is water (look up the property of water) d. Calculate the pressure drop in the tube over 10 cm.

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

Attached is the full solution

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M angle IJK = 57 degrees and m angle IJL = 20°. Find m angle LJK.
Debora [2.8K]

From the diagram given, it can be seen that

m\angle IJK=m\angle IJL+m\angle LJK

The question gives us

mm

Therefore, we can find m

Hence

\begin{gathered} 57=20+m\angle LJK \\ m\angle LJK=57-20 \\ m\angle LJK=37^{\circ} \end{gathered}

Thus, m 37°.

6 0
1 year ago
If D=20 miles when T=15 minutes, write a proportion to find D for T=20 minutes
Igoryamba
D/20=20/15

d=400/15

d=80/3

d=26 2/3 miles
8 0
3 years ago
16
aliya0001 [1]

Answer:

Step-by-step explanation:

3(1-4)=2(2-6)

3-12=4-12

-9= -8

Is there a variable?

5 0
3 years ago
Find the unit rate for 75% high-fiber chimp food to 25% high -protein chimp food
sammy [17]

Answer:  The answer is 3.


Step-by-step explanation:  We are given to find the unit rate for 75% high-fibre chimp food to 25% high -protein chimp food.

For that, we need to divide the quantity of fibre in food by the quantity of protein present in the food.

Fibre present in the food is given by

f_f=75\%=\dfrac{75}{100}=\dfrac{3}{4}.

And protein present in the food is

f_p=25\%=\dfrac{25}{100}=\dfrac{1}{4}.

Therefore, the unit rate of high-fibre chimp food to high-protein chimp food is

U=\dfrac{\frac{3}{4}}{\dfrac{1}{4}}=3.

Thus, the answer is 3.

7 0
3 years ago
Find the equation of the line between the points (10, – 5) and ( - 2,0).
Natali5045456 [20]

Answer <u>(assuming it can be in slope-intercept form)</u>:

y = -\frac{5}{12} x-\frac{5}{6}  

Step-by-step explanation:

1) First, find the slope of the line between the two points by using the slope formula, m  = \frac{y_2-y_1}{x_2-x_1}. Substitute the x and y values of the given points into the formula and solve:

m = \frac{(0)-(-5)}{(-2)-(10)} \\m = \frac{0+5}{-2-10} \\m=\frac{5}{-12}

Thus, the slope of the line is -\frac{5}{12}.

2) Next, use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line in point-slope form. Substitute values for m, x_1, and y_1 in the formula.

Since m represents the slope, substitute -\frac{5}{12} in its place. Since x_1 and y_1 represent the x and y values of one point the line intersects, choose any of the given points (it doesn't matter which one, it will equal the same thing) and substitute its x and y values into the formula as well. (I chose (-2,0), as seen below.) Then, isolate y and expand the right side in the resulting equation to find the equation of the line in slope-intercept form:

y-(0)=-\frac{5}{12} (x-(-2))\\y-0 = -\frac{5}{12} (x+2)\\y = -\frac{5}{12} x-\frac{5}{6}

3 0
3 years ago
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