Y-2= -3/4(x-6)
y=-3/4(x-6)+2
y=-3/4x+9/2+2
y=-3/4x+13/2
so for example if x=1 then y=5.76
or if x= 5 then y=2.75
√49z²
= √(7z)². [ here, Square cancles sq. root]
= 7z
May be Helpful.
Thank you!
The expression (-2 - 6i)-(-2-4i) to a + bi form is 0 - 2i.
Complete question.
Simplify the expression to a + bi form:
(-2 - 6i)-(-2-4i)
Square root of any negative number are expressed as a complex number. For example i = √-1
Complex numbers are generally written in the format z = x+iy
Given the expression (-2 - 6i)-(-2-4i)), in expansion:
(-2 - 6i)-(-2-4i)
= -2 - 6i + 2+4i
Collect the like terms
= (-2 + 2) - 6i + 4i
= 0 - 2i
Therefore the expression (-2 - 6i)-(-2-4i) to a + bi form is 0 - 2i.
Learn more on complex number here: brainly.com/question/12375854
|x-10| when x = -8
| - 8 - 10 | = |-18| = 18 <==
