The length of a rectangle is 2 in longer than its width. if the perimeter of the rectangle is 44 in , find its area.

2 answers:

7 0

P = 2(L + W)
P = 44
L = W + 2

44 = 2(W + 2 + W)
44 = 2(2W + 2)
44 = 4W + 4
44 - 4 = 4W
40 = 4W
40/4 = W
10 = W

L = W + 2
L = 10 + 2
L = 12

A = L * W
L = 12
W = 10

A = 12 * 10
A = 120 square inches <===

Tpy6a [65]3 years ago

3 0

The are of the rectangle would be 120 bcause the perimeter is 44 and the lenght is 2in bigger then the width and 10+10+12+12=44 so if you do length times width you get 12*10=12

You might be interested in

The perimeter of a rectangle is 15x + 17y. If the length is 7/2x + 7y then find the width of the rectangle.

EastWind [94]

Answer:

84 c. –25 6. 119 7. –28 36 8a. 4 b. 52 LESSON EI.B: ANSWERS 709 Topic EI .... The length is 11 inches, and the width is 7 inches. ... 15x – 10 = 2x + 6 1 5 10. x = 1 11. y = 8x – 5 12. x = y + 8 8 49. .... 5xy 3 – 17x 2y + 8xy + 16x 3y – 7x 10. x 3y 2z – 10x 2y + 14x 2z + 3xy 2 – 25xz 2 LESSON ... 2 > y > –5 F a 4x 3 y 5 4y 3 x 22.

Step-by-step explanation:

5 0

3 years ago

5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is

AleksandrR [38]

Answer:

$\frac{16r^3}{3}$

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

$\int\limits^r_a {2(x^2+r^2 )} \, dx$

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

$\frac{16r^3}{3}$

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0

2 years ago

An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t

Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .