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2 years ago

What is the the value of x? Enter uour answer in the box. 91°, 8x+3°,10x-4°

Mathematics

2 answers:

klemol [59]2 years ago

8 0

Answer:

The value of x is 5

Step-by-step explanation:

In triangle ABC

Using Angle Sum property of triangle to find the value of x.

Angle Sum property: The sum of all angles of a triangle is 180.

$\angle A+\angle B+\angle C=180^{\circ}$

$91^{\circ}+(10x-4)^{\circ}+(8x+3)^{\circ}=180^{\circ}$

$10x+8x+90=180$

$18x=180-90$

$x=5$

Hence, The value of x is 5

zzz [600]2 years ago

5 0

Answer:

x = 5 is the right answer.

Step-by-step explanation:

As we know sum of all angles in a triangle is 180°.Therefore in this question we will form an equation.

Sum of all the angles of a triangle = 180

91 + 10x - 4 +8x +3 = 180

90 + 18x = 180

18x + 90 - 90 = 180 - 90

18x = 90

x = 90÷18 = 5

Therefore x = 5 is the right answer.

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You deposit $75 in a savings account that earns 5% annual interest compounded yearly. Find the balance in the account after the

Nana76 [90]

Hi there
The formula is
A=p (1+r)^t
A future value
P present value 75
R interest rate 0.05
T time

After 1 year the balance is
A=75×(1+0.05)
A=78.75

After 2 years
A=75×(1+0.05)^(2)
A=82.69

After 5 years
A=75×(1+0.05)^(5)
A=95.72

After 20 years
A=75×(1+0.05)^(20)
A=198.99 round
A=199

Hope it helps

7 0

2 years ago

I got letter C as my answer, is that correct?

lisov135 [29]

Yes it is C if you do the math and simplify it that is what you’ll get

4 0

2 years ago

Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t

pashok25 [27]

Direct computation:

Parameterize the top part of the circle $x^2+y^2=1$ by

$\vec r(t)=(x(t),y(t))=(\cos t,\sin t)$

with $0\le t\le\pi$ , and the line segment by

$\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)$

with $0\le t\le1$ . Then

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)$

$=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt$

$=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}$

Using the fundamental theorem of calculus:

The integral can be written as

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}$

If there happens to be a scalar function $f$ such that $\vec F=\nabla f$ , then $\vec F$ is conservative and the integral is path-independent, so we only need to worry about the value of $f$ at the path's endpoints.

This requires

$\dfrac{\partial f}{\partial x}=\sin x\implies f(x,y)=-\cos x+g(y)$

$\dfrac{\partial f}{\partial y}=\cos y=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\sin y+C$

So we have

$f(x,y)=-\cos x+\sin y+C$

which means $\vec F$ is indeed conservative. By the fundamental theorem, we have

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=f(2,-\pi)-f(1,0)=-\cos2-(-\cos1)=\boxed{\cos1-\cos2}$

3 0

2 years ago

Solve the following equation: lim x->0 sin3x/5x^3-4x.

goblinko [34]

Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0

3 0

2 years ago

What is the absolute value of -4 - the square root of -2

ollegr [7]

The answer is 8 it should be

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2 years ago

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