Let's say the amount of nickels you have is hmm "n"
and the amount of dimes you have is "d"
there are 5cents in one nickel, so, if "n" is the total amount of nickels you have, that means 5 * n cents or 5n
there are 10cents in one dime, so, if "d" is the total amount of dimes you have, that means 10*d or 10d
whatever 5n and 10d are, we know that their sum is 595
since the total amount the counter said you have is, only 595 cents
thus 5n + 10d = 595
solve for either, "d" or "n", and graph that
what are three likely combinations? well, just pick three points off that graph
Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again
first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice
Answer:
7:3
Step-by-step explanation:
think of it as a fraction
5% of 18,000 is 900 , hope this helps.
I think it’s C sorry if I’m wrong
