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nekit [7.7K]
3 years ago
13

Mrs.gitterman gave a quiz to each of her three math classes. Each of her classes have 12 students. When she found the mean for e

ach class, she was surprised to see that the mean for each class was 80%. However looking at individuals scores, she found that the distribution of scores in each class looked very different.
Mathematics
2 answers:
kodGreya [7K]3 years ago
6 0

Answer:

4

Step-by-step explanation:

Ivahew [28]3 years ago
3 0

Answer:

4

Step-by-step explanation:

4

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Gabrielle's age is two times mikhall's age. the sum of their ages is 54. what is mikhall's age?
Elodia [21]

Answer:

27

Step-by-step explanation:

54/2

27x2=54 and they said 2 times

4 0
3 years ago
Read 2 more answers
Please help!!!!!<br> One third of a number x is no more than 15.
Nitella [24]

Answer:

1/3x is less than or equal to 15

Step-by-step explanation:

assuming you want an equation?

1/3x is less than or equal to 15

its this sign < with line under (srry i don't have the symbol)

7 0
3 years ago
What does x equal to? “?” = x Solve by using fractions and round to the nearest hundredth if necessary
Anna007 [38]

Answer:

3.5 inches

Step-by-step explanation:

We can rotate the figure to the left 90 degrees clockwise so that it becomes same orientation as the figure to the right.

Since they are similar figures, their corresponding sides are proportional.

The 4 inch side of left figure corresponds to 16 in side of right side figure.

The "?" inch side of left figure corresponds to 14 in side of right side figure.

We can replace "?" with "x" and setup two ratios and equate them:

\frac{4}{16}=\frac{x}{14}

Now, we can cross multiply and solve for x:

\frac{4}{16}=\frac{x}{14}\\16x=4*14\\16x=56\\x=\frac{56}{16}\\x=3.5

Hence,

the unknown side marked "?" is equal to 3.5 inches

6 0
3 years ago
The cosine equation for a function that has a period of 4 straight pi and an amplitude of 8
lara [203]

Answer:

y=4sin[2(x−π2)]−6

Step-by-step explanation:

The standard form of a sine function is

y=asin[b(x−h)]+k

where

•a : is the amplitude,

•2π/b : is the period,

•h : is the phase shift, and

•k : is the vertical displacement.

We start with classic

y=sinx :

graph{(y-sin(x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

(The circle at (0,0) is for a point of reference.)

The amplitude of this function is

a=1 .To make the amplitude 4, we need

a to be 4 times as large, so we set

a=4

.

Our function is now

y=4sinx ,and looks like:

graph{(y-4sin(x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

The period of this function—the distance between repetitions—right now is

2π , with b=1

.To make the period π , we need to make the repetitions twice as frequent, so we need

b=normal period/desired period

=2π/π=2

.

Our function is now

y=4sin(2x), and looks like: graph

{(y-4sin(2x))(x^2+y^2-0.075)=0 [-15, 15, -11, 5]}

This function currently has no phase shift, since

h=0

. To induce a phace shift, we need to offset

xby the desired amount, which in this case is

π2 to the right. A phase shift right means a positive

h, so we set

h = π2

.

Our function is now

y=4sin[2(x−π2)] , and looks like:graph

{(y-4sin(2(x-pi/2)))((x-pi/2)^2+y^2-0.075)=0 [-15, 15, -11, 5]}

Finally, the function currently has no vertical displacement, since

k=0

.To displace the graph 6 units down, we set

k=−6

.

Our function is now

y=4sin[2(x−π2)]−6, and looks like:graph {(y-4sin(2(x-pi/2))+6)((x-pi/2)^2+(y+6)^2-0.075)=0 [-15, 15, -11, 5]}

6 0
3 years ago
Which statement CANNOT be represented by the expression t - 16
faltersainse [42]

Answer:

no statement

Step-by-step explanation:

List the statements pls

3 0
3 years ago
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