Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
Answer:
huh
Explanation:
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Answer:
#include <iostream>
#include <vector>
using namespace std;
void calGPA();
vector<int> g;
vector<int> h;
int main(){
char pushMore = 'y';
int fg, fh;
for (;;){
if (pushMore == 'n'){
break;
} else{
cout<< "Enter integer for grade: ";
cin>> fg;
cout<< "Enter integer for credit hours: ";
cin>> fh;
g.push_back(fg);
h.push_back(fh);
cout<< "Do you want to add more grade and credit hours? y/n: ";
cin>> pushMore;
}
}
calGPA();
}
void calGPA(){
double total = 0, GPA;
for (int i = 0; i < g.size(); ++i) {
total += g.at(i) * h.at(i) ;
}
cout<< "The GPA is : "<< total/g.size();
}
Explanation:
The C++ source code above defines two vectors 'g' and 'h'. The latter holds the grades of a student while the former holds the credit hours for the subject taken. The void 'calGPA' function calculates and prints the student's GPA.
Answer:
Quantizing error
Explanation:
In digitisation of analog signal refers to the rounding off of values which are approximately equal to the analog signals. The method of sampling chooses a few point on the analog signal and then these points are joined to round off the value to a near stabilised value. such process is known as Quantization. For any system, during its functioning, there is always a difference in the values of its input and output. The processing of the system results in an error, which is the difference of those values.
The difference between an input value and its quantized value is called a Quantization Error. A Quantizer is a logarithmic function that performs Quantization rounding off the value. An analog-to-digital converter (ADC) works as a quantizer.
In the business cycle, the term that best fits the labeled point on the graph of Production output vs Time is Contraction
