Jewelery maker has
24 jade beads
30 teak Beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
Answer:
k = -8
Step-by-step explanation:
The location of P is ...
P = (2A+B)/3 = (2·2+5, 2·1-8)/3 = (3, -2)
Putting this point into the equation for the line, we have ...
2(3) -(-2) +k = 0
8 +k = 0
k = -8
First, multiply 4*2x-4*-5= 8x-20.
Second, add 15 to 8x-20
Third, that would equal 8x-20+15=11
Fourth, 15+-20= -5
Fifth, 8x-5=11
Sixth, add +5 to -5 and +5 to 11= 8x=16
Last, do 8x/8x and 16/8x
The answer is x=2
We have been given that ∠Q is an acute angle such that 
. We are asked to find the measure of angle Q to nearest tenth of a degree.
We will use arctan to solve for measure of angle Q as:
Now we will use calculator to solve for Q as:
Upon rounding to nearest tenth of degree, we will get:
Therefore, measure of angle Q is approximately 2.3 degrees.
