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Kazeer [188]
3 years ago
6

How many many weeks are in 105 days?​

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer: 15 weeks

Step-by-step explanation:

Because there are 7 days in a week, simply divide 105/7 to get 15 weeks.

Hope it helps <3

Klio2033 [76]3 years ago
3 0

Hi there! Hopefully this helps!

----------------------------------------------------------------------------------------------------

<em>Answer: There are </em><u><em>15 weeks in 105 days</em></u><em>.</em>

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em>Since there are </em><u><em>7 days in a week</em></u><em>, we need to </em><u><em>divide </em></u><u><em>the time value by 7 .</em></u>

<em>Like this:</em>

<em />

<em>105 </em><em>/ 7 = 15</em><em>.</em>

<em />

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Reil [10]

Answer:  G

<u>Step-by-step explanation:</u>

(x, y) → (\frac{1}{8}x, \frac{1}{8}y)

means that the new quadrilateral will be \frac{1}{8} the size of the original quadrilateral, so it will be smaller because the it maps to a fraction that is less than 1.

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Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















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3 years ago
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I am not sure, but I checked my answer and I am right. Hope this helps, thank you :) !!

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3 years ago
To find the product 3/7 x 4/9 Cameron simplified 3/7 to 1/7 and then mulitiplied the fractions 1/7 and 4/9 to find the product 4
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3 years ago
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What is the area of this trapezoid?
Sonbull [250]
Find the area of the square first
Area = Length x Width
Area = 12 x 9
Area = 108

Find the area of the right triangles
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Since there is 2 triangles multiply by 2
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8 0
3 years ago
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