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ratelena [41]
3 years ago
13

Can someone please help me I don't get this at all

Mathematics
2 answers:
zavuch27 [327]3 years ago
8 0

It might help to replace m with some positive number. Let's say m = 5

So everywhere you see an 'm', in an inequality or a graph, replace it with 5. You can pick any other positive number if you prefer.

---------------------------------------------

Inequality a.

x/m < -1

x/5 < -1 ... replace m with 5

x < -5 ... multiply both sides by 5

The graph will have an open circle at -5 and shading to the left

This describes graph C after you replace m with 5.

Note: if m = 5, then   -m = -5.

---------------------------------------------

Inequality b.

x/m > 1

x/5 > 1

x > 5

We'll have an open circle at 5 with shading to the right. This describes graph A.

---------------------------------------------

Inequality c.

x/m < 1

x/5 < 1

x < 5

This describes graph B since it has an open circle at 5 and shading to the left.

---------------------------------------------

Inequality d.

-x/m < 1

-x/5 < 1

x > -5 .... inequality sign flips when we multiply both sides by a negative number

The graph would be graph D because there is an open circle at

-m = -5

and we shade to the right of this open circle.

goldfiish [28.3K]3 years ago
5 0

Answer:

A and D          B and A               C and B                 D and C

Step-by-step explanation:

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Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

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5 0
2 years ago
Can someone help me solve this question? It’s similar to the previous ones! Thank you!
luda_lava [24]

Answer:

\boxed{\sf \ \ \ (-2x+-9)(1x+3)=-2x^2-15x-27 \ \ \ }

the coefficient c is -27

Step-by-step explanation:

hello

(-2x+-9)(1x+3)=(-2x-9)(x+3)=-2x(x+3)-9(x+3)=-2x^2-6x-9x-27\\=-2x^2-15x-27

hope this helps

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3 years ago
What is the pattern sequence for 1,2,5,6,9
alisha [4.7K]

Step-by-step explanation:

It is 1 then 2 then 3

Bcz 1 2 5 6 9 10 11 12 13

5 0
3 years ago
Read 2 more answers
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