In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.
<h3>Where is the
electric potential, when the particle moved?</h3>
The charge field system's electric potential energy rose. The particle experiences an electric force that is directed against the x-axis. It is pushed uphill by an outside force, which raises the potential energy.
When a charge to be moved against an applied electric field, electric potential energy is needed. A charge must be moved through a stronger electric field with more energy than it would require to carry it via a weaker electric field.
In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.
The electric potential energy of the charge field system:
- (a) increase
- (b) remain constant
- (c) decrease
- (d) change unpredictably
The correct option is a).
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The pressure value is given by the equation,

Where,
represents the density of the liquid
g= gravity
h= Heigth
A) For the measurement of the guage pressure we have the data data,



Replacing we get,

P_g = 12395Pa[/tex]
In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,
B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

Answer:
Option A
The apparent change in frequency of waves due to the motion of a source
Explanation:
Doppler effect is the apparent change in frequency of waves due to the motion of a source. Doppler effect occurs when the source of waves moves towards the observer which causes emission of successive wave crests to be closer to the observer compared to the previous wave crest. This phenomenon was named after Austrian Physicist called Christian Doppler
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
Answer:
The thrust of the jet engine is 4188.81 N.
Explanation:
Given that,
Speed = 260 m/s
Rate in air= 53.3 kg/s
Rate of fuel = 3.63 kg/s
Relative speed = 317 m/s
We need to calculate the rate of mass change in the rocket
Using formula of rate of mass

Put the value into the formula


We need to calculate the thrust of the jet engine
Using formula of thrust

Put the value into the formula


Hence, The thrust of the jet engine is 4188.81 N.