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Len [333]
3 years ago
9

How many σ bonds and π bonds does the co2 molecule have?

Physics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

2 \sigma bonds and 2 \pi bonds

Explanation:

If we consider the the bonding in the CO_{2} molecule:

O = 1s^{2}\ 2s^{2}\ 2p^{4}

C = 1s^{2}\ 2s^{2}\ 2p^{2}

Thus carbon forms double bonds with oxygen:

O = C = O

Now,

We know that double bond comprises of a \sigma\ bond and a \pi \ bond

Since, in the CO_{2}, there are 2 double bonds thus there are 2 \sigma bonds and 2 \pi bonds in the molecules.

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A point charge Q moves on the x-axis in the positive direction with a speed of 290 m/s. A point P is on the y-axis at y = +60 mm
aliina [53]

Answer:

Explanation:

Magnetic field due to a moving charge

B = μ₀ / 4π x (qv x r)/r²

Given

B = .3 X 10⁻⁶ T,

r = 60 x 10⁻³ m

Putting these values in the given equation

.3 x 10⁻⁶ = 10⁻⁷ x qvsinθ /( 60 x 10⁻³)²

θ = 90 °

qv = 10.8 x 10⁻³

At point P

Sinθ  = 60 / 72

r² = 72 x 72 x 10⁻⁶

B = \frac{10^{-7}\times108\times10^{-4}\times60}{72\times72\times72\times10^{-6}}

= 0.17 μT

8 0
4 years ago
. The earth revolves around the sun in the counterclockwise direction, completing one full revolution about every 365 days. In r
LuckyWell [14K]

Answer:

Explanation:

The earth makes in  365 day 1 revolution

The earth makes in 1 day     1 / 365 revolutions

1 / 365 revolution per day

n = 1 / 365 per day .

n is called frequency of revolutions .

Angular velocity = 2π n

= 2 π x 1 / 365

= .0172 radian / day

6 0
3 years ago
5. A man in a car is listening to the radio. The radio station is broadcasting at a frequency of 85 MHz from two radio transmitt
nasty-shy [4]

Answer:

Speed = 0.00392 m/s

Explanation:

Solution:

Frequency of the radio = 85 MHz

If we have the frequency, we can calculate the wavelength of the radio wave.

As we know,

Frequency = speed of light/wavelength

wavelength = c/f

c = speed of light = 3 x 10^{8} m/s

So,

Wavelength =  3 x 10^{8} m/s / 85 x 10^{6} Hz

Wavelength = 3.5294 m

Man gets disturbed reception at t = 15 min

t = 15 x 60 = 900 s

t = 900 s

Speed = distance/time

Here, distance is wavelength. So,

Speed =  3.5294 m / 900 s

Speed = 0.00392 m/s

Hence, the man's car is going with speed of 0.00392 m/s

3 0
3 years ago
You roll a toy car, and it moves 10 meters in five seconds. What is the car's velocity?
maks197457 [2]
  • Displacement = 10 m
  • Time = 5 s
  • We know,
  • velocity \:  \:  =  \frac{displacement}{time}  \\
  • Therefore, the car's velocity
  • =  \frac{10}{5} m/s \\  = 2m/s
<h3>Answer:</h3>

The car's velocity is 2 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T
padilas [110]

Answer:

Explanation:

First case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball rebounds and move in opposite direction. This shows that the ball have a velocity after impulse let say v

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

I=m(v+u)

I=m(v+0.3)

I¹=0.3m+mv. Equation 1

Second case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball is at rest, this show that the final velocity is v=0

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

I=m(v+u)

In this case v=0 u=0.3m/s

I=m(0+0.3)

I²=0.3m. Equation 2

If we compare impulse 1 (I¹) to impulse 2 (I²)

Subtract equation 2 from 1

We have, I¹ - I² =0.3m+mv -0.3m

I¹ - I² =mv

I¹ =mv+I²

We notice that the first impulse (I¹) is greater than second impulse (I²) by mv.

The correct answer is A

5 0
3 years ago
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