83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
Explanation:
Molarity or molar concentration is the number of moles of solute that can be dissolved in 1 L of a solution.
let us find the number of moles
n=C*V Concentration is 0.75M
Volume is 1000ml.
n= 0.75*1
n= 0.75
This means there are 0.75 moles of CaCl2 in 1000 ml of solution of .75M.
Molar mass of CaCl2 is = 40.08+ 2(35.5)
= 110.98 gms
Thus 1 MOLE OF CaCl2 weighs 110.98
so 0.75 moles will weigh 110.98*0.75
= 83.235 grams of CaCl2 is required to make 1 litre of 0.75M solution.
The most likely place to find algae is in the middle.
Answer:
It depends on the type of microscope that you have
Explanation:
For example, in the case that you have a fluorescence microscope, it is possible to create a fusion construct of the domain fused to the Green Fluorescence Protein (GFP) and then introduce it into the cell. The observation of fluorescence from this construct enables to confirm the existence of the signal sequence (i.e., the C-terminal domain) in the organelle
Independently is the right option