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pshichka [43]
4 years ago
5

Choose the correct simplification of the expression −5x2(4x − 6x2 − 3).

Mathematics
2 answers:
Dominik [7]4 years ago
8 0
If you would like to solve -5x^2 * (4x - 6x^2 - 3), you can do this using the following steps:

-5x^2 * (4x - 6x^2 - 3) = (-5x^2) * 4x - (-5x^2) * 6x^2 - (-5x^2) * 3 = -20x^3 + 30x^4 + 15x^2 = 30x^4 - 20x^3 + 15x^2

The correct result would be <span>30x^4 - 20x^3 + 15x^2.</span>
Kazeer [188]4 years ago
8 0

Answer:

Option A is correct

30x^4-20x^3+15x^2

Step-by-step explanation:

The distributive property says that:

a \cdot (x +y +z) = a\cdot x+ a\cdot y+ a\cdot z

Given the expression: 5x^2(4x-6x^2-3)

Using distributive property :

-5x^2 \cdot (4x) - 5x^2 \cdot (-6x^2) -5x^2 \cdot (-3)

Use: x^a \cdot x^b = x^{a+b}

then;

-20x^3+30x^4+15x^2

or

30x^4-20x^3+15x^2

Therefore, the correct simplification of the given  expression is 30x^4-20x^3+15x^2

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-2x + 8

Step-by-step explanation:

I applied the distribution technique to the original question.

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ms smith paid 125 to have her hair colored and cut. If she tips her hairdresser 15% of her bill, how much was the tip
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Give an example of two monomials with a quotient of -3n²/m​
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3 years ago
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Sedaia [141]

Answer:

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

<u>Equation 1:</u>

5(x-2) = 5x-7

5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3

As both sides are not equal, equation has no solution.

<u>Equation 2:</u>

-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\

As both sides are equal the equation has infinite many solutions.

<u>Equation 3:</u>

-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3

As x=3, the equation has only one solution.

<u>Equation 4:</u>

6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11

The equation has no solution.

Hence,

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

6 0
3 years ago
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