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pshichka [43]
4 years ago
5

Choose the correct simplification of the expression −5x2(4x − 6x2 − 3).

Mathematics
2 answers:
Dominik [7]4 years ago
8 0
If you would like to solve -5x^2 * (4x - 6x^2 - 3), you can do this using the following steps:

-5x^2 * (4x - 6x^2 - 3) = (-5x^2) * 4x - (-5x^2) * 6x^2 - (-5x^2) * 3 = -20x^3 + 30x^4 + 15x^2 = 30x^4 - 20x^3 + 15x^2

The correct result would be <span>30x^4 - 20x^3 + 15x^2.</span>
Kazeer [188]4 years ago
8 0

Answer:

Option A is correct

30x^4-20x^3+15x^2

Step-by-step explanation:

The distributive property says that:

a \cdot (x +y +z) = a\cdot x+ a\cdot y+ a\cdot z

Given the expression: 5x^2(4x-6x^2-3)

Using distributive property :

-5x^2 \cdot (4x) - 5x^2 \cdot (-6x^2) -5x^2 \cdot (-3)

Use: x^a \cdot x^b = x^{a+b}

then;

-20x^3+30x^4+15x^2

or

30x^4-20x^3+15x^2

Therefore, the correct simplification of the given  expression is 30x^4-20x^3+15x^2

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True if you’re solving for a solution but if it’s the solution has a negative since it can’t be read as positive
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Simplify. 13(1−14)2 Enter your answer, as a simplified fraction, in the box.
babymother [125]

Answer.

-78 it’s not a fraction

7 0
4 years ago
the theoretical probability choosing a purple marble out of a 2/3 bag is. The bag has 16 purple marbles. How many marbles are in
algol [13]

Answer:

24 marbles

Step-by-step explanation:

P( purple) = 2/3 = purple/total

                   2/3 = 16/total

Using cross products

                  2 * total = 3 *16

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8 0
3 years ago
Which of the following is NOT true? Question 19 options: (3x2y5)3=27x6y15 (1000x12y20z−3)0=1 52‾‾√3=523 42×43= 165
bixtya [17]

Answer:


Step-by-step explanation:

Lets try to simplify each to check which one is incorrect so it will be NOT true

first one is :

distribute the exponent so :

(3x^2y^5)^3 =3^3x^{2*3}y^{5*3}

27x^6y^{15} CORRECT

Second one is :

(1000x^{12}y^{20}z^{-30})^{0} =1

CORRECT because anything raised to exponent 0 is 1 .

Last one is :

4^2 *4^3 = 4^{2+3}\\=4^{6}\\=(4)^{2*3}\\=16^{3}

so Last is<em> INCORRECT</em>



5 0
3 years ago
Solve the following system of equations. Show all work and solutions.
Alekssandra [29.7K]

Answer: (0, 1), (-1, -3)

Given two equation's:

  1. y = 2x² + 6x + 1
  2. y = −4x² + 1

<u>Solve them simultaneously</u>:

\sf 2x^2 + 6x + 1 = -4x^2 + 1

\sf 2x^2 + 4x^2 = 1 - 1

\sf 6x^2 + 6x = 0

\sf 6x(x + 1) = 0

\sf 6x = 0, \  x + 1 = 0

\sf x = 0,  \ x = -1

(a) When x = 0,     y = −4(0)² + 1 = 1

(b) When x = -1,    y = -4(-1)² + 1 = -3

Solution: (x, y) → (0, 1), (-1, -3)

3 0
2 years ago
Read 2 more answers
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