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kogti [31]
3 years ago
9

A piece of antimony with a mass of 17.41 g is submerged in 46.3 cm3 of water in a graduated cylinder. The water level increases

to 48.9 cm3. The correct value for the density of antimony from these data is: + CHEM133 Course Hero
Chemistry
1 answer:
kobusy [5.1K]3 years ago
8 0

Answer:

6.696 g/cm3

Explanation:

From the question;

Mass = 17.41g

Volume of water before = 46.3 cm3

Volume of water after = 48.9 cm3

Volume of antimony = Volume after - Volume before = 48.9 - 46.3 = 2.6 cm3

Density = Mass / Volume

Density = 17.41 / 2.6 = 6.696 g/cm3

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Answer:criminal behavior

Explanation:

Edge 2021

5 0
3 years ago
What is the mass of a magnesium block that measures 2.00 cm
skad [1K]

Answer:

m = 31.284 grams

Explanation:

Given that,

The dimension of a magnesium block is 2.00 cm  x 3.00 cm x 3.00 cm.

The density of magnesium is, d = 1.738 g/cm³

We need to find the mass of the magnesium block. We know that the density of an object is given by its mass per unit its volume. So,

d=\dfrac{m}{V}\\\\\text{Where m=mass}\\\\m=d\times V\\\\m=1.738\ g/cm^3\times (2\times 3\times 3)\ cm^3\\\\m=31.284\ \text{grams}

So, the mass of the block is 31.284 grams.

5 0
3 years ago
Can someone help me with this pls
diamong [38]
The chemical elements are arranged in order of increasing atomic number. Answer A.
7 0
3 years ago
Read 2 more answers
Calcula la masa atómica del Hierro y las partículas subatómicas de cada uno de sus isótopos. Fe-54 (5.82%), Fe-56 (91.66%), Fe-5
tino4ka555 [31]

Answer:

La masa atómica del hierro es 55.847 gramos por mol.

Explanation:

Las masas molares de Fe_{54}, Fe_{56}, Fe_{57} y Fe_{58} son 53.940 gramos por mol, 55.935 gramos por mol, 56.935 gramos por mol y 57.933 gramos por mol, respectivamente. La masa atómica del hierro se determina mediante el siguiente promedio ponderado:

M_{Fe} = \frac{5.82}{100}\times \left(53.940\,\frac{g}{mol} \right)+\frac{91.66}{100}\times (55.935\,\frac{g}{mol})+\frac{2.19}{100}\times \left(56.935\,\frac{g}{mol} \right)+\frac{0.33}{100}\times \left(57.933\,\frac{g}{mol} \right)

M_{Fe} = 55.847\,\frac{g}{mol}

La masa atómica del hierro es 55.847 gramos por mol.

8 0
3 years ago
Calculate the missing variables in each experiment below using Avogadro’s law.
blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

5 0
3 years ago
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