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klemol [59]
2 years ago
15

What are the rules for writing chemical formulas

Chemistry
1 answer:
Alenkasestr [34]2 years ago
6 0
1: the symbol of the metal should be written first.
2: the valency of the elements or radicals should be interchanged.
You might be interested in
A 500 ml aqueous solution of na3po4 was prepared using 82g of the solute. what is the molarity​
liraira [26]

Answer:

1 M

Explanation:

The molarity of a solution, M, is a measure of the concentration of that solution and it refers to the number of moles of solute (mol) per liter (L) of solution. The molarity (M) can be calculated using the formula:

M = number of moles (n) /volume (V)

In this question, a 500 ml aqueous solution of Na3PO4 was prepared using 82g of the solute.

Molar mass of Na3PO4 = 23(3) + 15 + 16(4)

= 69 + 31 + 64

= 164g/mol

Mole = mass/molar mass

mole = 82/164

mole = 0.5 mol

Volume in Litres (L) = 500 ml ÷ 1000 = 0.500L

Therefore, Molarity (M) = 0.5/0.500

Molarity = 1 M or 1 mol/L

7 0
3 years ago
How many hydrogen atoms are in water, H2O?<br><br> A) 1<br> B) 2<br> C) 3<br> D) 0
pishuonlain [190]
There are two hydrogen atoms in one molecule of water.

The answer is B) 2
8 0
2 years ago
Read 2 more answers
List in ascending order the different layers of atmosphere, their heights, and main their features. Help please!!! :•)
Anika [276]

Answer:

Troposphere

Stratosphere

Mesosphere

Thermosphere

Exosphere

Explanation:

These are all listed in ascending order, hope this helps!

6 0
3 years ago
How many moles is 2.80 x 10^24 atoms of silicon
neonofarm [45]
The answer that i found is 4.650
3 0
3 years ago
The mass of a deuterium nucleus 21H is less than its components masses. Calculate the mass defect.________ amu
Inessa [10]

Answer:

The mass defect of a deuterium nucleus is 0.001848 amu.

Explanation:

The deuterium is:

^{A}_{Z}X \rightarrow ^{2}_{1}H  

The mass defect can be calculated by using the following equation:

\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}

Where:

Z: is the number of protons = 1

A: is the mass number = 2      

m_{p}: is the proton's mass = 1.00728 amu  

m_{n}: is the neutron's mass = 1.00867 amu

m_{a}: is the mass of deuterium = 2.01410178 amu

Then, the mass defect is:

\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu

Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.

I hope it helps you!  

5 0
3 years ago
Read 2 more answers
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