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kotykmax [81]
3 years ago
5

Match the vocabulary terms to their definitions.

Chemistry
2 answers:
vesna_86 [32]3 years ago
7 0

Answer:

1. The standard metric unit of length is a meter.

2. A proposed explanation for a scientific problem is a hypothesis.

3. The standard unit of volume is a liter.

4. The curved top surface of a liquid column is the meniscus.

5. A quantity in an experiment that remains unchanges or constant is a controlled variable (control)

6. The amount of matter in an object is mass.

Dennis_Churaev [7]3 years ago
6 0

Explanation:

1. Standard metric unit of length  → meter

Unit is defined as the quantity that is used as a standard for measurement.  Meter, Centimeters, hectometers are the units which is used to express length of a substance.

2. A proposed explanation for a scientific problem   → hypothesis

Hypothesis is defined as explanation or supposition made on the basis of limited evidence for a specific process or phenomena.

3. Standard unit of volume  →  liter

Liter is the unit which is used to express volume occupied by the substance.

4. The curved top surface of a liquid column    → meniscus

Liquids from two types of meniscus :

Concave shaped curve due to adhesive forces and is dominating inside the glass.

Convex  shaped curve due to due to cohesive forces and is dominating on the top of glass.

5. A quantity in an experiment that remains unchanged or constant  →  control

Control variable is an experimental variable which is kept unchanged or remains constant through out the course of an experiment.

6. Amount of matter in an object  →  mass

Mass of the body is defined as quantity of present in a given object. It is a constant quantity.

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Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

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E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

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Also, let the constant rate for the catalyzed biochemical reaction = K₁

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If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

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Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

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