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3 years ago

Match the vocabulary terms to their definitions.

Chemistry

2 answers:

vesna_86 [32]3 years ago

7 0

Answer:

1. The standard metric unit of length is a meter.

2. A proposed explanation for a scientific problem is a hypothesis.

3. The standard unit of volume is a liter.

4. The curved top surface of a liquid column is the meniscus.

5. A quantity in an experiment that remains unchanges or constant is a controlled variable (control)

6. The amount of matter in an object is mass.

Dennis_Churaev [7]3 years ago

6 0

Explanation:

1. Standard metric unit of length → meter

Unit is defined as the quantity that is used as a standard for measurement. Meter, Centimeters, hectometers are the units which is used to express length of a substance.

2. A proposed explanation for a scientific problem → hypothesis

Hypothesis is defined as explanation or supposition made on the basis of limited evidence for a specific process or phenomena.

3. Standard unit of volume → liter

Liter is the unit which is used to express volume occupied by the substance.

4. The curved top surface of a liquid column → meniscus

Liquids from two types of meniscus :

Concave shaped curve due to adhesive forces and is dominating inside the glass.

Convex shaped curve due to due to cohesive forces and is dominating on the top of glass.

5. A quantity in an experiment that remains unchanged or constant → control

Control variable is an experimental variable which is kept unchanged or remains constant through out the course of an experiment.

6. Amount of matter in an object → mass

Mass of the body is defined as quantity of present in a given object. It is a constant quantity.

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Alina [70]

Answer:

Explanation:

Step 1:

The balanced equation for the reaction.

Fe2O3(s) + 6HCl(aq) → 2FeCl3(aq) + 3H2O

Step 2 :

Determination of the masses of HCl and Fe2O3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Fe2O3 = 159.70g/mol

Molar mass of HCl = 36.46 g/mol

Mass of HCl from the balanced equation = 6 x 36.46 = 218.76g

From the balanced equation above,

159.70g of Fe2O3 reacted with 218.76g of HCl

Step 3:

Determination of the mass of HCl needed to react with 439g of Fe2O3. This is illustrated below:

From the balanced equation above,

159.70g of Fe2O3 reacted with 218.76g of HCl.

Therefore, 439g of Fe2O3 will react with = (439 x 218.76) /159.70 = 601.35g of HCl.

Step 4:

Conversion of 601.35g of HCl to mole. This is illustrated below:

Molar mass of HCl = 36.46 g/mol

Mass of HCl = 601.35g

Number of mole = Mass/Molar Mass

Number of mole of HCl = 601.35/36.46

Number of mole of HCl = 16.49 moles

Step 5:

Determination of the volume of the HCl that reacted.

This is illustrated below:

Mole of HCl = 16.49 moles

Molarity of HCl = 5.50 M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 16.49/5.5

Volume of HCl = 3L

Therefore the volume of HCl needed for the reaction is 3L

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2 years ago

why is the term "ionic" used when describing compounds formed from a metal element and a nonmetal element?

nordsb [41]

Ionic compounds form when metals transfer valence electrons to nonmetals. Ionic compounds exist as crystals rather than molecules.

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2 years ago

An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having

dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass 2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007 (1-x) = 1.008

2.014x + 1.007 - 1.007 x = 1.008

2.014x - 1.007x = 1.008 - 1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass 2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

0.9991 × 100= 99.91%

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2 years ago

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3 years ago

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aivan3 [116]

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