Question

Help! Anyone can you explain?

Answer 1

Answer:

$\texttt{Probability that the first ball will be red and the second will be blue = }\frac{9}{55}$

Step-by-step explanation:

Total number of balls = 3 + 2 + 6 = 11

Probability is the ratio of number of favorable outcome to total number of outcomes.

$\texttt{Probability that the first ball will be red = }\frac{\texttt{Total number of red balls}}{\texttt{Total number of balls}}\\\\\texttt{Probability that the first ball will be red = }\frac{3}{11}$

Now we have 10 balls in which 6 are blue.

$\texttt{Probability that the second ball will be blue = }\frac{\texttt{Total number of blue balls}}{\texttt{Total number of balls}}\\\\\texttt{Probability that the first ball will be red = }\frac{6}{10}=\frac{3}{5}$

$\texttt{Probability that the first ball will be red and the second will be blue = }\frac{3}{11}\times \frac{3}{5}\\\\\texttt{Probability that the first ball will be red and the second will be blue = }\frac{9}{55}$

Answer 2

Answer: 9/55

P(1st = red and 2nd = blue)

= (3/11) x (6/10)

= 18/110

= 9/55

To find the probability of something happening,

= (number of desired outcomes) / (total number of outcomes)

If you are finding the probability of more than one thing happening at the same time, you multiply the probability of both things happening together