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adell [148]
4 years ago
11

????????????????????????

Mathematics
1 answer:
Fed [463]4 years ago
3 0
A=10*8+((8-6)(15-10))/2
A=10*8+(2*5)/2
A=10*8+10/2
A=10*8+5
A=80+5
A=85 feet 
Therefore the answer is D

Hope this helps :)
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5 0
3 years ago
Does anybody know the answer???
maria [59]

Answer:

Linear polynomial.

Step-by-step explanation:

A linear polynomial is written with a degree 1. An example of a linear polynomials includes 3x + 5. This is what 5b - 1 is.

Hope it helps!

7 0
3 years ago
Question Help
klasskru [66]

Answer:

16 times

Step-by-step explanation:

\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

If only the radius is changed, the change in volume will be proportionate to the multiplicative factor squared.

\sf \implies Volume =\dfrac{1}{3} \pi (ar)^2h=\dfrac{1}{3} \pi (a^2)r^2h

Therefore, if the cone is quadrupled (multiplied by 4), the volume of the larger cone will be 4² times greater than the volume of the smaller cone, so <u>16 times greater </u>than the smaller cone.

<h3><u>Proof</u></h3>

Given:

  • radius = 6
  • height = 9

Substituting the given values into the formula:

\sf \implies Volume =\dfrac{1}{3} \pi (6)^2(9)=108 \pi \: \:cubic\:units

If the radius is quadrupled:

  • radius = 6 × 4 = 24
  • height = 9

Substituting the new given values into the formula:

\sf \implies Volume =\dfrac{1}{3} \pi (24)^2(9)=1728 \pi \: \:cubic\:units

To find the number of times greater the volume of the large cone is than the volume of the smaller cone, divide their volumes:

\sf \implies \dfrac{V_{large}}{V_{small}}=\dfrac{1728\pi}{108\pi}=16

So the volume of the larger cone is <u>16 times greater</u> than the volume of the smaller cone.

4 0
2 years ago
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6 0
3 years ago
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hichkok12 [17]

Answer:

23.1

Step-by-step explanation:

14/20*x/33

Cross multiply

14*33=20*x

462=20*x

462/20=x

23.1=x

Hope this helps :)

5 0
3 years ago
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