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Olin [163]
3 years ago
5

Pls help with my homework, 5,11,12

Mathematics
1 answer:
Ilya [14]3 years ago
4 0
These will be the answers

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Using the midpoint method, calculate the price elasticity of demand of Good Z using the following information: When the price of
exis [7]

Answer: (B) The price elasticity of demand for good Z = 0.86

Step-by-step explanation:

The formula for determining elasticity of demand by using the midpoint method is

(Q2 - Q1)/[(Q2 + Q1)/2] / (P2 - P1)/[(P2 + P1)/2]

Where

P1 is the initial price of the item.

P2 is the final price of the item.

Q1 is the initial quantity demanded for the item.

Q2 is the final quantity demanded for the item.

From the information given,

P1 = 10

P2 = 15

Q1 = 85

Q2 = 60

The price elasticity of demand for good Z = (60 - 85)/[(60 + 85)/2] / (15 - 10)/[(15 + 10)/2]

= (-25/72.5) / (5/12.5) = -25/72.5 × 12.5/5

= - 312.5/362.5 = - 0.86

6 0
3 years ago
Select the relations that are functions.
Arlecino [84]

Answer:

Depending on how the input of each function defined,

  • The first choice \left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace,
  • The third choice \left\lbrace(1, a),\, (2, a), \, (3, a)\right\rbrace
  • The fourth choice \left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

  • be defined for all elements in the domain, and
  • map each element from the domain to exactly one element in the range.

The second choice can't be a function since the element a from the domain is mapped to more than one element in the range.

Keep in mind that a function should be defined for all elements in its domain. For the first relation to be a function, its domain needs to be \lbrace a,\, 6, \, C\rbrace. Similarly, the domain for the third and fourth relations should be \lbrace 1,\, 2, \, 3\rbrace and \lbrace a,\, b, \, c\rbrace

8 0
3 years ago
Can someone help me with this?
Damm [24]

Answer:

<h2>780</h2>

Step-by-step explanation:

What is the sum of the series 5^n from n=1 to 4.

5^1 + 5^2 + 5^3+ 5^4 =

5 + 25 + 125 + 625 =780

3 0
3 years ago
Hello again,
Nataly [62]

Answer: 395

Step-by-step explanation:

201+99+95

5 0
3 years ago
(3x3 - 2x2 + 4) - (2x2 + 14) =
gogolik [260]
The answer is c u welcome
6 0
3 years ago
Read 2 more answers
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