2 years ago

If y varies directly as x and y = 8 when x = 4, what is the value of y when x = 16?

Mathematics

1 answer:

const2013 [10]2 years ago

5 0

Answer:

Step-by-step explanation:

x=4 was multiplyed by 4 to get to x=16 so you have to multiply y=8 by 4 to get the answer which is 32

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Read 2 more answers

Consider the function f(x)=x^2+bx-49 where b is a constant. if the function has an axis of symmetry at x = 8, what is the value

Jlenok [28]

For this case we have the following equation:
f (x) = x ^ 2 + bx-49
Deriving we have:
f '(x) = 2x + b
We match zero:
0 = 2x + b
We clear x:
x = -b / 2
The axis of symmetry is at x = 8, therefore:
x = -b / 2 = 8
Clearing b:
b = -2 * (8)
b = -16
Answer:
the value of b is:
b = -16

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