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3 years ago

10

A bag contains 60 marbles 12 are blue 8 are white 18 are red 16 are green 6 are yellow what is the probability that a green marb

le is chosen

1 answer:

zhuklara [117]3 years ago

7 0

16/60 chance, since out of the whole 60 marbles, only 16 are green. The simplified version is 4/15. In a percentage, it would be a 26% chance.

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A student expanded an expression, as shown. Is the student's work correct? Explain why or why not.

alex41 [277]

The work is incorrect.

(-6) multiplies both terms inside parentheses. For some reason, the student changed the sign of that multiplier for the second term. The second term of the result should have a positive sign, the result of multiplying (-6)(-2/13) = +12/13.

4 0

2 years ago

Read 2 more answers

Calculate the discriminant and use it to determine how many real-number roots the equation has.

Vladimir79 [104]

In a quadratic equation with the general formula of:

ax^2 + bx + c = 0

The discriminant is equal to b^2 - 4(a)(c). If the answer is a perfect square, then there are two real numbers. If not, then there are no real number root.

The discriminant for this equation is

(-6)^2 - 4(3)(1) = 24

Since 24 is not a perfect square, there are no real number roots.

4 0

2 years ago

Write an equation for each problem. The square of a number is 8 more than twice the number.

avanturin [10]

Answer:

The equation is equal to

$x^{2}=2x+8$

Step-by-step explanation:

Let

x -----> the number

we know that

The equation that represented the problem is equal to

$x^{2}=2x+8$

$x^{2}-2x-8=0$

Solve the quadratic equation by graphing

The solution are x=-2 and x=4

see the attached figure

therefore

The number can be -2 or 4

3 0

3 years ago

In a game a player draws and replaces a card from a deck 2 times. The possible outcomes and payouts are shown. What is the

Goshia [24]

<u>Given</u>:

Given that in a game a player draws and replaces a card from a deck 2 times.

The possible outcomes and payouts are given.

We need to determine the expected value for someone playing the game.

<u>Expected value:</u>

The expected value for someone playing the game can be determined by

$EV=(\frac{26}{52})(\$ 20)+(\frac{52}{52})(\$4)+(\frac{52}{52})(\$ 0)+(\frac{26}{52})(-\$12)$

Simplifying the values, we have;

$EV=(\frac{1}{2})(\$ 20)+(1)(\$4)+(1)(\$ 0)+(\frac{1}{2})(-\$12)$

Dividing the terms, we get;

$EV=\$ 10+\$4+\$ 0+-\$6$

Adding, we have;

$EV=\$ 8$

Thus, the expected value for someone playing the game is $8

3 0

2 years ago

I don’t know how to solve this

snow_lady [41]

First you have to find the area of the WHOLE BOX. So you multiply,
8×7=56
Then find the area of the small box,
5×4=20
It says take away the area of the small box from the whole box and you should do just that: 56-20=36
The area of the shaded region is 36cm²

5 0

3 years ago

Read 2 more answers