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andriy [413]
3 years ago
12

How many milliliters of a 0.40 m solution of hydrochloric acid are necessary to neutralize 25 ml of a 0.20 m sodium hydroxide so

lution?
Chemistry
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

12.5 mL of HCl

Explanation:

The balanced chemical equation for the neutralization reaction is as follows

NaOH + HCl —> NaCl + H2O

Molar ratio of NaOH to HCl is 1:1

For neutralization to happen the number of NaOH moles is equal to the number of HCl moles

Number of NaOH moles reacted - 0.20 mol/L x 0.025 L = 0.005 mol

Therefore number of HCl moles reacted - 0.005 mol

Concentration of HCl is 0.40 mol/L

Concentration = number of moles / volume

Rearranging the equation

Volume = number of moles / concentration

Volume = 0.005 mol / 0.40 mol/L

= 0.0125 L

Volume of HCl added is 12.5 mL

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2 years ago
the volume of a cylindrical tin can with a top and a bottom is to be 16Ï cubic inches. if a minimum amount of tin is to be used
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Answer:

The required height of the tin can is given by the height at the minimum value of the surface area function of the tin can

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Reason:

The given information on the tin can are;

Volume of the tin can = 16·π in.³

The amount of tin to be used = Minimum amount

The height of the can in inches required

Solution;

Let h, represent the height of the can, we have;

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Which gives;

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4·π·(r³ - 8) = r² × 0

r³ = 8

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The radius of the tin can, r = 2 inches

The

The height of the tin can, h = 4 inches

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brainly.com/question/14316282

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Earth's first semi-permanent atmosphere consisted of abundant water vapor, carbon dioxide, nitrogen, ammonia, and traces of meth
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A solution is prepared by pipetting 20.00 mL of a 1.00 x 10-3 M NaCl solution into a 250.0 mL volumetric flask. The flask is dil
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Answer:

The concentration of the newly prepared solution is 8 * 10^-5 M

Explanation:

The most common way to solve this problem is to use the following formula

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c2 = 0.00008 M = 8 * 10^-5 M

The concentration of the newly prepared solution is 8 * 10^-5 M

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