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Mamont248 [21]
3 years ago
13

A solution is prepared by pipetting 20.00 mL of a 1.00 x 10-3 M NaCl solution into a 250.0 mL volumetric flask. The flask is dil

uted to the mark with deionized water. Calculate the concentration of the newly prepared solution.
Chemistry
1 answer:
oee [108]3 years ago
3 0

Answer:

The concentration of the newly prepared solution is 8 * 10^-5 M

Explanation:

The most common way to solve this problem is to use the following formula

c1*V1 = c2*V2

with c1 = 1 * 10^-3 M

with V1 = 20 mL = 0.02 L

with c2 = TO BE DETERMINED

with V2 = 250 mL = O.250 L

10^-3 * 0.02 L = c2 * 0.250L

0.00002 = c2 * 0.250L

c2 = 0.00002 / 0.250 L

c2 = 0.00008 M = 8 * 10^-5 M

The concentration of the newly prepared solution is 8 * 10^-5 M

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In a saturated solution, extra solid X would remain solid, dissolve in an unsaturated solution, and crystallize in a supersaturated one.

A solution is said to be saturated when there is a maximum amount of solute present that has been dissolved in the solvent. As a result, the system is in an equilibrium between the dissolved and undissolved solutes: A solution is considered to be unsaturated if the solute concentration is less than the equilibrium solubility. A supersaturated solution is one that has more solute than is necessary to generate a saturated solution at a given temperature.

Learn more about Supersaturated here-

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5 0
2 years ago
In an estuary, _____.
lapo4ka [179]

B; Seawater mixes with freshwater so the water has intermediate salinity

Explanation:

In an estuary, seawater mixes with freshwater so the water has intermediate salinity. Estuaries are usually located in transitional environments.

  • Estuary is the wide part of a river where it nears the sea.
  • This is called a transitional zone.
  • Water from continental rivers usually fresh are brought in close contact with ocean water that is salty.
  • The water here is said to be brackish as it is intermediate between salt and seawater.
  • Organisms living in such terrain must be be well adapted to changing salinity.

Learn more:

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6 0
3 years ago
The functional structure of a protein is its _________________ structure, which is ultimately determined by the ________________
Dmitriy789 [7]

Answer:

A.

Explanation:

The <u>tertiary structure </u>of proteins is related to the interactions between the amino acids of the <u>primary structure</u>. Thus, these interactions give it a specific three-dimensional configuration which is very sensitive to <u>functionality</u>.

For example, <u>allosteric inhibitions</u> are related to this concept. When the <u>inhibitor</u> changes the tertiary structure of the protein it loses all <u>activity</u> and for the catalysis of the reaction.

Thus, the primary structure (which is related to the specific <u>sequence of amino acids</u>) will determine the tertiary structure since the chain folds will be a consequence of<u> intra-amino acid interactions</u>.

8 0
4 years ago
Read 2 more answers
What is the mass in grams of 7.23 miles of dinitrogen trioxide?
nevsk [136]

Answer:

549.563868

Explanation:

1 mole is equal to 1 moles N2O3, or 76.0116 grams. so 76.0116 x 7.23 = 549.563868

3 0
3 years ago
Determine the relative formula mass of hexasodium difluoride using the periodic table below. A. 138 g/mol B. 176 g/mol C. 20 g/m
laila [671]

Answer:

Option B. 176g/mol

Explanation:

We'll begin by writing the chemical formula for hexasodium difluoride. This is given below:

Hexasodium means 6 sodium atom

Difluoride means 2 fluorine atom.

Therefore, the formula for hexasodium difluoride is Na6F2.

The relative formula mass of a compound is obtained by simply adding the atomic masses of the elements present in the compound.

Thus, the relative formula mass of hexasodium difluoride, Na6F2 can be obtained as follow:

Molar mass of Na = 23g/mol

Molar mass of F = 19g/mol

Relative formula mass Na6F2 = (23x6) + (19x2)

= 138 + 38

= 176g/mol

Therefore, the relative formula mass of hexasodium difluoride, Na6F2 is 176g/mol

3 0
4 years ago
Read 2 more answers
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