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Olenka [21]
3 years ago
5

1)

Chemistry
2 answers:
dalvyx [7]3 years ago
7 0

All I know for certain is Potential energy is converted to kinetic energy.

That is the answer to question 3.

Andrej [43]3 years ago
4 0
1.<span>B) <span>the subscript
2.<span>B)<span>CO2 </span></span>.
3.B) potential energy is converted into kinetic energy
4.A) A roller coaster at the top of a hill
6.C) in motion
7.D) weed whacker full of gas
8.B) potential energy only
9.</span></span>A) baking soda
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Six protons, six electrons, and six neutrons. The atom you are looking for is Carbon. The mass number is 12.

Mass number = protons + neutrons 
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Substance
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lithium 3

Explanation:

This is because lithium has three protons

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Which solute would be more effective at lowering the freezing point of water: MgCl2 and KNO3? Explain.
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Answer:

AlCl₃.

Explanation:

Adding solute to water causes depression of the boiling point.

The depression in freezing point (ΔTf) can be calculated using the relation:

ΔTf = i.Kf.m,

where, ΔTf is the depression in freezing point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kf is the molal depression constant of water.

m is the molality of the solution (m = 1.0 m, for all solutions).

(1) NaCl:

i for NaCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (NaCl) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(2) MgCl₂:

i for MgCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

∴ ΔTb for (MgCl₂) = i.Kb.m = (3)(Kf)(1.0 m) = 3(Kf).

(3) NaCl:

i for KBr = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

∴ ΔTb for (KBr) = i.Kb.m = (2)(Kf)(1.0 m) = 2(Kf).

(4) AlCl₃:

i for AlCl₃ = no. of particles produced when the substance is dissolved/no. of original particle = 4/1 = 4.

∴ ΔTb for (CoCl₃) = i.Kb.m = (4)(Kf)(1.0 m) = 4(Kf).

So, the ionic compound will lower the freezing point the most is: AlCl₃

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Answer:

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i think

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