Answer:
600
Step-by-step explanation:
anything times 1 is itself
It's important that you share the complete question. What is your goal here? Double check to ensure that you have copied the entire problem correctly.
The general equation of a circle is x^2 + y^2 = r^2. Here we know that the circle passes thru two points: (-3,2) and (1,5). Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.
Subst. the known values (of the first point) into this equation: (-3)^2 + (2)^2 = r^2. Then 9 + 4 = 13 = r^2.
Let's check this. Assuming that the equation of this specific circle is
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.
(1)^2 + (5)^2 = 13 is not true, unfortunately.
(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).
Check the original problem. If it's different from that which you have shared, share the correct version and come back here for further help.
Answer:
sin²x
Step-by-step explanation:
we have
(1 − cos x)(1 + cos x)=1-cos²x
Remember that
sin²x+cos²x=1 ------> i-cos²x=sin²x
therefore
(1 − cos x)(1 + cos x)=sin²x
