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Alekssandra [29.7K]
2 years ago
8

What integer is between 27 + 1 and 72 ?

Mathematics
1 answer:
alexira [117]2 years ago
8 0

Answer:

there's kinda alot of numbers there pal

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I need help with this it’s saying the “blank” Method would be the best for solving this system of equations
aleksandrvk [35]

Answer:

-12+4y=x..............1

6(-12+4y)+4y=8

-72+24y+4y=8

28y=80

y=3.33

-12+4(3.33)=x

1.32=x

5 0
2 years ago
6.) -2x + y = -1<br><br> X Y<br> -4<br> -3<br> -2<br> 1<br> 0
MrRa [10]

Answer:

Step-by-step explanation:

i ASSUME THE QUESTION IS TO DETERMINE Y?  

Rearrange the equation  to y = 2x - 1 and solve for each value of x

<u>X</u>  <u>Y</u>

-4  -9

-3  -7

-2  -5

1   1

0  -1

7 0
2 years ago
How can you determine if a fraction is greater than less than or equal to a decimal
saul85 [17]
Change the fraction into a decimal
3 0
3 years ago
A function f(x)=3x+12.
seraphim [82]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822258

_______________


•  Function:   f(x) = 3x + 12.


A.  Finding the inverse of f.

The composition of f with its inverse results in the identity function:

(f o g)(x) = x

f[ g(x) ] = x

3 · g(x) + 12 = x

3 · g(x) = x – 12

              x – 12
g(x)  =  ⸺⸺
                 3

               x 
g(x)  =  ⸺  –  4    <———    this is the inverse of f.
               3

________


B.  Verifying that the composition of f and g gives us the identity function:

•  \mathsf{(f\circ g)(x)}

\mathsf{=f\big[g(x)\big]}\\\\\\ \mathsf{=3\cdot \left(\dfrac{x}{3}-4\right)+12}\\\\\\&#10;\mathsf{=\diagup\hspace{-7}3\cdot \dfrac{x}{\diagup\hspace{-7}3}-3\cdot 4+12}\\\\\\&#10;\mathsf{=x-12+12}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}


and also

•  \mathsf{(g\circ f)(x)}

\mathsf{=g\big[f(x)\big]}\\\\\\ \mathsf{=\dfrac{f(x)}{3}-4}\\\\\\ \mathsf{=\dfrac{3x+12}{3}-4}\\\\\\&#10;\mathsf{=\dfrac{\diagup\hspace{-7}3\cdot (x+4)}{\diagup\hspace{-7}3}-4}\\\\\\&#10;\mathsf{=x+4-4}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}

________


C.  Since f and g are inverse, then

f(g(– 2))

= (f o g)(– 2)

= – 2          <span>✔
</span>

•  Call h the compositon of f and g. So,

h(x) = (f o g)(x)

h(x) = x


As you can see above, there is no restriction for h. Therefore, the domain of h is R (all real numbers).


I hope this helps. =)

5 0
3 years ago
Evaluate the Following.
sweet [91]

Answer:

29. 161

33. 4329

37. 163664/25

Explanation:

I hope it helps you

3 0
2 years ago
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