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Softa [21]
3 years ago
14

You set up monthly recurring payments of $110.03, $45.66, and $22.87. How much will your recurring payments total over one year?

Mathematics
2 answers:
nekit [7.7K]3 years ago
7 0

Answer:

Option b $2,142.72

Step-by-step explanation:

You set up monthly recurring payments of $110.03, $45.66 and $22.87

So the total payments  for one month = 110.03 + 45.66 + 22.87 = $178.56

The total recurring payment for one month is $178.56

To find out total payments for one year, we multiply it with 12

$178.56 × 12 = $2,142.72

$2,142.72 would your recurring payments total one year.

AlladinOne [14]3 years ago
5 0
The answer is B 2,142.72 because when you add it all up then multiply by 12 it will equal that.
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Please solve with explanation (high points)
IgorLugansk [536]

So, we know that:

A=\dfrac{1}{2}ab\\P=a+b+c\\a^2+b^2=c^2

We also know that (a+b)^2=a^2+2ab+b^2. We will use that fact to find c in terms of A and P.

A=\dfrac{1}{2}ab\Rightarrow 2ab=4A\\P=a+b+c\Rightarrow a+b=P-c

Therefore:

(P-c)^2=c^2+4A\\P^2-2cP+c^2=c^2+4a\\2cP=P^2-4A\\c=\dfrac{P^2-4A}{2P}

7 0
2 years ago
(255)/(6)*(672)/(9)+(37)/(9) <br> How do you work this out step by step??
koban [17]
Step 1. Type it into a Google search box or calculator. (You need to use a calculator anyway.) The result is 3177 4/9.

If you're doing this according to the Order of Operations, you do the multiplication and division left to right. This means the first calculation you do is
  255/6 = 42.5
Next, you multiply by 672
  42.5*672 = 28560
Then divide by 9
  28560/9 = 3173 3/9

You continue by doing the division
  37/9 = 4 1/9

And finish by adding the two results
  3173 3/9 + 4 1/9 = 3174 4/9

_____
If you're doing this by hand, you can recognize the first term as the product of two fractions, so is the product of numerators divided by the product of denominators.
  (255*672)/(6*9)
Using your knowledge of divisibility rules, you can do the division 672/6 to simplify this to
  (255*112)/9
Now, the first term and the second term have the same denominator, so you can add the numerators before you do the division.
  (255*112 + 37)/9 = (28560 + 37)/9 = 28597/9
You end up having to do only two simple divisions, rather than 3 of them.
  28597/9 = 3177 4/9

7 0
3 years ago
Which polynomial function has a leading coefficient of 1 and roots 21 and 31 with multiplicity 1?
schepotkina [342]

Answer:

Which i think is the first one, there may just be a typing error.

Step-by-step explanation:

A polynomial of order n has the following format:

f(x) = a(x - x_{0})(x - x_{1})...(x - x_{n-1})

In which a is the leading coefficient, x_{0}, x_{1},..., x_{n-1} are the roots.

If a root appears m times, they are said to have multiplicity m.

Leading coefficient of 1 and roots 21 and 31 with multiplicity 1

f(x) = 1(x - 21)(x - 31)

So the correct answer is:

f(x) = 1(x - 21)(x - 31)

Which i think is the first one, there may just be a typing error.

8 0
3 years ago
What is a equivalent rational number to 1.28 repeating?
goblinko [34]
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3 years ago
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gladu [14]
The correct answer is b
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3 years ago
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