All categories

3 years ago

Abcd please help!!!!

Mathematics

1 answer:

Gnom [1K]3 years ago

5 0

The angle VXU is larger than a 90 degree angle half of an exact straight angle (180 degrees) so it’s obtuse. The only angle larger 90 degree is D :)

You might be interested in

Find the whole if 2.5% of n is 0.01.

Lunna [17]

Answer:

$2.5\% \: of \: n = 0.01 \\ \frac{2.5}{100} \times n = 0.01 \\ 2.5n = 1 \\ n = 0.4$

5 0

3 years ago

Enter the decimal equivalent of 6/8

ikadub [295]

Answer:

.75

Step-by-step explanation:

6/8 can be simplified to 3/4, if that helps.

3 0

3 years ago

Solve the system of equations. x=2y-5 -3x=-6y+15

Pachacha [2.7K]

Answer:

x = 2y - 5

Step-by-step explanation:

7 0

3 years ago

Please someone help me with the question

Yuki888 [10]

Answer:

$\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Exponential Rule [Multiplying]: $\displaystyle b^m \cdot b^n = b^{m + n}$

Calculus

Derivatives

Derivative Notation

eˣ Derivative: $\displaystyle \frac{d}{dx}[e^x] = e^x$

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x \cdot e^x]$

$\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x \cdot e^{2x}]$

Step 2: Differentiate

$\displaystyle \frac{d}{dx}[e^{2x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x]e^x + e^x\frac{d}{dx}[e^x]$
[Derivative] eˣ Derivative: $\displaystyle \frac{d}{dx}[e^{2x}] = e^x \cdot e^x + e^x \cdot e^x$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{2x}] = e^{2x} + e^{2x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x]e^{2x} + e^x\frac{d}{dx}[e^{2x}]$
[Derivative] eˣ Derivatives: $\displaystyle \frac{d}{dx}[e^{3x}] = e^x(e^{2x}) + e^x(2e^{2x})$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{3x}] = e^{3x} + 2e^{3x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

8 0

3 years ago

14 points someone please help me quick!

Shtirlitz [24]

The E3 is the same as writing 10^3.

The answer would be 7.9 x 10^3

3 0

4 years ago