Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
D
Step-by-step explanation:
there are 9 digits.
and round it off to the nearest hundred million which is 3.
There are 8 digits before the 3... so 10 gets to the power of 8.___ 10⁸
3,0×10⁸ m.s^-1
Answer:
Step-by-step explanation:
So we are assuming only the times listed count toward telling us how long the game was, so you just add the three numbers together. 155, 175 and 30
i think that's the answer