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MaRussiya [10]
3 years ago
12

Find the quotient of 90 over -10

Mathematics
2 answers:
OLEGan [10]3 years ago
5 0
Hi! The answer is -9 because 90/-10 = -9
I hope this helps you, Goodluck! :)
vodka [1.7K]3 years ago
3 0

90/-10

= 9/-1

= -9

So, -9 is the quotient.

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To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi
Alika [10]

Given:

The expression is 5+4\times 2+6-2\times 2-1.

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

5+4\times 2+6-2\times 2-1

Now,

(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1

(5+4)\times 2+6-2\times 2-1=18+6-5

(5+4)\times 2+6-2\times 2-1=18+1

(5+4)\times 2+6-2\times 2-1=19

There are more ways to apply the parenthesis, but we do not get 19.

5+4*\left(2+6\right)-2*2-1=32\neq 19

5+4*2+\left(6-2\right)*2-1=20\neq 19

5+4*2+6-2*\left(2-1\right)=17\neq 19

And many more possibilities.

Therefore, the expression after inserting the parentheses is (5+4)\times 2+6-2\times 2-1.

6 0
3 years ago
Think about the function f(x) = 10 - x3. What is the input, or independent variable? f(x) x y
denpristay [2]

Answer:

The input or independent variable is x.

Step-by-step explanation:

3 0
2 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

6 0
3 years ago
The letters of the alphabet are written on cards and places in a brown paper bag. What is the probability or drawing a vowel, re
ehidna [41]

Answer:

0.1%

Step-by-step explanation:

:D

3 0
3 years ago
Let A and B be two disjoint events such that P(A) = .30 and P(B) = .60. What is P(A and B)? 0.18 0.72 0.90 0 none of the above
antiseptic1488 [7]

Answer:

0

Step-by-step explanation:

If two events are disjoing (aka mutually exclusive) that means that there is 0 overlap or the intersection equals 0

So the probability of A <em>and </em>B occuring is 0 (because P(A∩B)= 0)

4 0
3 years ago
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