Answer:
[2] x = -5y - 4
// Plug this in for variable x in equation [1]
[1] 2•(-5y-4) - 5y = 22
[1] - 15y = 30
// Solve equation [1] for the variable y
[1] 15y = - 30
[1] y = - 2
// By now we know this much :
x = -5y-4
y = -2
// Use the y value to solve for x
x = -5(-2)-4 = 6
Solution :
{x,y} = {6,-2}
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Terms and Topics
Linear Equations with Two Unknowns
Solving Linear Equations by Substitution
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Algebra - Linear Systems with Two Variables
Step-by-step explanation:
Answer:
2,995 or 35,940(?)
Step-by-step explanation:
I don't exactly remember how to do this so, I'll show you two different ways I solved this
Use the formula I=P*r*t
I=Interest
P=Principal
r=rate
t=time
To solve this you'll have to...
The principal is 29,950, the rate is 5% but it'll become a decimal which is 0.05, and the time is 2
Put it into the formula form 29,950*0.05*2= 2,995 in interest
Or...
You'll use the same formula, but this time multiply 0.05 by 12 since there are 12 months in one year which is 0.6, so...
29,950*0.6*2=35,940 in interest
I hope one works!
A=pir^2
a=pi13^2
a=169pi
a=530.66 square cm
50 - 40x ≥ 200
-40x ≥ -300
x ≤ 7.5
40$ can be withdrawn from the account 7 weeks if she wants to maintain a balance at least 200<span />