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Fittoniya [83]
3 years ago
12

Jeans are $20 for 2 pairs. Kerry spent $40 on jeans.How many pairs did she buy?​

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0
Kerry bought 2 pairs of jeans
Leona [35]3 years ago
5 0

Answer:Kerry would have bought 2 pairs of jeans

Step-by-step explanation:

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What is the answer to this? i can’t figure it out.
Svetach [21]

9514 1404 393

Answer:

  25 +0i

Step-by-step explanation:

The conjugate of a complex number is that number with the sign of the imaginary part reversed.

For z = -3+4i, its conjugate z* is -3-4i. The product of z and z* is ...

  (-3 +4i)(-3 -4i) = -3(-3 -4i) +4i(-3 -4i)

  = 9 +12i -12i -16i² = 9 +16 = 25

The real part of the product is 25; the imaginary part is 0.

  (-3 +4i)(-3 -4i) = 25 +0i

_____

You may have noticed that (z)(z*) = |z|², the sum of the squares of the real and imaginary parts. It is always a non-negative real number.

8 0
2 years ago
Please help ASAP I will give brainliest!
GaryK [48]

Answer:

6 minutes

Step-by-step explanation:

2 degrees per minute

so you need 12 degrees so 12/2 = 6 degrees

3 0
3 years ago
7th-grade math help me, please :(
IgorC [24]

Answer:

71 remainder 80

Step-by-step explanation:

\frac{28480}{400}=71\:remainder\:80\\\\\frac{28480}{400}=71\frac{80}{400}\\

7 0
2 years ago
Read 2 more answers
Four artists open a business selling paintings and agree to split the profits equally. They spent $150 on supplies. If their tot
pashok25 [27]
First, I would subtract 150 from 870. You get 720. Then I would divide that equally among the four artists. 720/4=180. So each person's share is $180.
8 0
2 years ago
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Complete the multiplication: AB. <br><br> A. <br> B. <br> C. <br> D.
Firdavs [7]
These array of numbers shown above are called matrices. These are rectangular arrays of number that are arranged in columns and rows. It is mostly useful in solving a system of linear equations. For example, you have these equations

x+3y=5
2x+y=1
x+y=10

In matrix form that would be

\left[\begin{array}{ccc}1&3&5\\2&1&1\\1&1&10\end{array}\right]

where the first column are the coefficients of x, the second column the coefficients of y and the third column is the constants, When you multiple matrices, just multiply the same number on the same column number and the same row number. For this problem, the solution is

\left[\begin{array}{ccc}3*2&0*8\\2*0.6&-1*3\end{array}\right] =  \left[\begin{array}{ccc}6&0\\1.2&-3\end{array}\right]

6 0
3 years ago
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