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Fittoniya [83]
3 years ago
12

Jeans are $20 for 2 pairs. Kerry spent $40 on jeans.How many pairs did she buy?​

Mathematics
2 answers:
stiks02 [169]3 years ago
7 0
Kerry bought 2 pairs of jeans
Leona [35]3 years ago
5 0

Answer:Kerry would have bought 2 pairs of jeans

Step-by-step explanation:

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Can someone help me with this problem. please
Kitty [74]

Answer:

Step-by-step explanation:

area = 30x + 30(x+3) + 30(2x)

= 30x + 30x+90 + 60x

= (120x + 90) m²

length of planting area = x + (x+3) + 2x = 4x+3 m

area = 30(4x+3) = (120x + 90) m²

x = 5

maple area = 30(5+3) = 240 m²

locust area = 30(2·5) = = 300 m²

8 0
2 years ago
What set notation best describes the range of the function graphed below ?
maxonik [38]

Answer:

I need a pic of the graph pleas3

Step-by-step explanation:

Dont mind this

7 0
1 year ago
Use an equation to find the value of k so that the line that passes through the given slope (1,3) , (5,k) m=2
scoray [572]

Answer:

The value of k with given points and slop = 11

Step-by-step explanation:

Given that a line passes through two points having slop (m) = 2

co ordinates of points are (1 , 3)   and (5 , k)

Now slop of line can be written as,

Slop = \frac{(y2 - y1)}{(x2 - x1)}

Or, m =  \frac{(y2 - y1)}{(x2 - x1)}

     2 =  \frac{(k - 3)}{(5 - 1)}

Or, 2 =  \frac{(k - 3)}{(4)}

So , k - 3 = 8

∴ K = 8+3 = 11

Hence the value of k with given points and slop = 11    Answer

5 0
2 years ago
How do i do this? the interquartile range? please help!
Irina18 [472]

Answer:

20

Step-by-step explanation:

3 0
3 years ago
3÷ 1/4. 7÷ 1/2. 1/5÷ 1/20. 1/2÷ 1/10. 1/7÷ 3.. help me solve all these please.​
Nina [5.8K]

Answer:

Step-by-step explanation:

Use KCF method for fraction division.

Keep the first fraction

Change the operation to multiplication

Flip the second fraction.

1) 3÷ (1/4) = 3*\frac{4}{1}= 12

2) 7 ÷ (1/2) = 7 * \frac{2}{1}=14

3) (1/5) ÷ (1/20) = \frac{1}{5}*\frac{20}{1}=4

4) (1/2) ÷ (1/10) = \frac{1}{2}*\frac{10}{1}=5

5) (1/7) ÷ 3 = \frac{1}{7}*\frac{1}{3}=\frac{1}{21}

7 0
2 years ago
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