To find which ratio is higher, we can first convert the ratios into fractions (that makes it easier, at least for me) and then simplify the fractions and see which one is greater.
Since ratios are basically division, 15:20 = 
, and
12:16 = 
Now we simplify these fractions. 15 and 20 have a GCF of 5, so taking out the common number gives us the simplified fraction of 
.
12 and 16 have a GCF of 4, so taking out the common number gives us the simplified fraction of . Since = , these ratios are the same.
Answer:
Minimum value of function 
is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :
Subject to constraints:
Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering 
, corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.
at A(0,9)
at B(3,9)
at C(3,6)
Minimum value of function is 63 occurs at point C (3,6).
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
Ray Of Light [21]
Answer:
(x-4)(x-4)(x+2)
Step-by-step explanation:
Given p(x) = x^3-6x^2+32 when it is divided by x - 4, the quotient gives
x^2-2x-8
Q(x) = P(x)/d(x)
x^3-6x^2+32/x- 4 = x^2-2x-8
Factorizing the quotient
x^2-2x-8
x^2-4x+2x-8
x(x-4)+2(x-4)
(x-4)(x+2)
Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)
Answer:
Following the rule of BIDMAS
we will solve the one inside the bracket first, Addition will be solved before subtraction
i.e ( 5+4-2) x ( - 2)
= ( 9-2) x (-2)
= 7 x -2
= - 14
Step-by-step explanation:
You take 3•4 to get 12, then you add a zero to that and get 120. You then multiply by six and get 720.
