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3 years ago

the diagram shows a rectangle four of these rectangles are put to together as shown calculate the shaded area

Mathematics

1 answer:

yawa3891 [41]3 years ago

6 0

Answer:

42cm squared

Step-by-step explanation:

You are taking 2 x 0.5cm of the smaller sides rectangles which is 1. Then what is left is 6x7 which is 42cm squared

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The flower color of bigleaf hydrangeas is determined by the soil's pH. A gardener growing blue hydrangeas believes that lime may

barxatty [35]

PH is calculated by the negative logarithm of the hydrogen concentration in a solution. Therefore, the pH in this case is:

pH = -log (0.0000006)
pH = 6.22

Therefore the correct answer among the choices is the last option, pH of 6 with a color pink.

8 0

3 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

WILL GIVE BRAINLIEST GUESS IF YOU HAVE 2 A parallelogram has an area of 224 square centimeters and a base length of 16 centimete

ivann1987 [24]

Answer:

Area = base * height

224 = 16 * height

height = 14

The height is 14 centimeters.

Your answer is c.

3 0

3 years ago

In 1980 (before the era of in-vitro fertilization), there were 3,612,258 births in the United States (according to the U.S. Cens

scoray [572]

Answer:

There was a 1.93% probability of having multiples (twins or more) in 1980.

Step-by-step explanation:

There were 3,612,258 births in the US in 1980.

Of those,

68339 + 1337 = 69676 were multiplies.

What was the probability of having multiples (twins or more) in 1980?

$P = \frac{69676}{3612258} = 0.0193$

There was a 1.93% probability of having multiples (twins or more) in 1980.

8 0

3 years ago

Find the product.<br> (3n - 1)(7n-7)

slega [8]

Answer:

21n² - 28n + 7

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

3n(7n - 7) - 1(7n - 7) ← distribute both parenthesis

= 21n² - 21n - 7n + 7 ← collect like terms

= 21n² - 28n + 7

6 0

3 years ago