<u>ANSWER</u>
The point 
lies on the straight line 
<u>EXPLANATION</u>
The given line is . It can be observed that the given straight line is in the point-slope form.
We can rewrite the equation in the point-slope form to obtain,
.
When we compare this to the general point-slope form, which given by the formula;
,
We can observe that,
and 
.
Hence the point, 
lies on
Answer:
<u>The correct answer is C. 14.6 feet</u>
Step-by-step explanation:
Information given to solve the case:
Length of the ladder = 15 feet
Distance from the base of the wall = 3.5 feet
Using the Pythagorean theorem for finding the height, because this is a right triangle:
h² = Length of the ladder ² - Distance from the base of the wall ²
h² = 15 ² - 3.5 ²
h² = 225 - 12.25
h² = 212.75
h = √ 212.75
h = 14.59
<u>h = 14.6 feet (Rounding to one decimal place)</u>
Answer: 3.751*10^18kg
Step-by-step explanation:
δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.
Calculating the density of air at 5km above earth surface
P = 5000m + 6370000m = 6.375*10^6m
δ = 619.09 -(.000097* 6.375*10^6)
δ = 0.715kg/m^3 = density
Since Mass = density*volume...equ2
To calculate volume of air around the spherical earth at height 5km
V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6
Substituting R and r in equation 2 to solve for volume of air
V = 1.085*10^21 - 1.08*10^21
V = 5.25*10^18m^3
Substituting δ and V into equation 2 to solve for mass of air
M = 0.715 * (5.25*10^18)
M = 3.751*10^18kg
3wx^2 it is the same as 5-2
