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3 years ago

the diagram shows a rectangle four of these rectangles are put to together as shown calculate the shaded area

Mathematics

1 answer:

yawa3891 [41]3 years ago

6 0

Answer:

42cm squared

Step-by-step explanation:

You are taking 2 x 0.5cm of the smaller sides rectangles which is 1. Then what is left is 6x7 which is 42cm squared

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How do I write the number 17,497,403 well i know how to do it inside standard but my equation says “Write the number Seventeen m

MrRa [10]

Step-by-step explanation:

Standard form is of course 17,497,403.

Expanded form is:

10,000,000 + 7,000,000 + 400,000 + 90,000 + 7,000 + 400 + 3

7 0

3 years ago

Which statement is true?

Dafna1 [17]

The second one is the true statement

7 0

3 years ago

Travelers who fail to cancel their hotel reservations when they have no intention of showing up are commonly referred to as no-s

notsponge [240]

Answer:

a) 0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) 0 is the most likely value for X.

Step-by-step explanation:

For each traveler who made a reservation, there are only two possible outcomes. Either they show up, or they do not. The probability of a traveler showing up is independent of other travelers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

No-show rate of 10%.

This means that $p = 0.1$

Four travelers who have made hotel reservations in this study.

This means that $n = 4$

a) What is the probability that at least two of the four selected will turn to be no-shows?

This is $P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

$P(X \geq 2) = P(X = 2) + P(X = 3) + P(X = 4) = 0.0486 + 0.0036 + 0.0001 = 0.0523$

0.0523 = 5.23% probability that at least two of the four selected will turn to be no-shows.

b) What is the most likely value for X?

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.1)^{0}.(0.9)^{4} = 0.6561$

$P(X = 1) = C_{4,1}.(0.1)^{1}.(0.9)^{3} = 0.2916$

$P(X = 2) = C_{4,2}.(0.1)^{2}.(0.9)^{2} = 0.0486$

$P(X = 3) = C_{4,3}.(0.1)^{3}.(0.9)^{1} = 0.0036$

$P(X = 4) = C_{4,4}.(0.1)^{4}.(0.9)^{0} = 0.0001$

X = 0 has the highest probability, which means that 0 is the most likely value for X.

7 0

3 years ago

2. Joyce waited three-quarters of an hour to

Evgen [1.6K]

Joyce waited 50 minutes waiting for the train

Step-by-step explanation:

divide 60 by 3 cause 3 quarters of an hour is 3/4 then you wanna take half an hour and add that (30 mins) getting 50 minutes

8 0

3 years ago

Please help out with this if you can.

Pepsi [2]

Answer:

3/7 and 4/17

Step-by-step explanation:

a) given that Shen is playing a game and the probability of unlocking the treasure test is 3/10.

To find the odds in favour of his character unlocking the treasure chest.

Since probability = 3/10 we have favourable and total are in the ratio 3:10

i.e. favourable:Favourable+unfavourable= 3:3+7

Hene odds= favourable:unfavourable =3/7

Answer is 3/7

b) Given that odds against choosing a blue block are 13/4

This means there are 4 blue blocks and 13 other colour blocks.

Total blocks= 13+4 =17

No of blue blocks = 4

Probability of selecting blue block=4/17

6 0

3 years ago