2. The picture shows a feeding trough that is shaped like a right prism.

A rectangle has perimeter, P, length, land width, w. Which of the following represents lin

almond37 [142]

Answer:

$l=\frac{P}{2}-w$ .

Step-by-step explanation:

The perimeter of a rectangle is the sum of it's side lengths.

A rectangle has 4 sides where it's opposite sides are congruent.

So if one side has measurement w, then there is another side that has measurement w.

If there is one side that has measurement l, then there is another side that has measurement l.

So if you add w+w+l+l you get 2w+2l.

They are giving us that the perimeter is P, so P=2w+2l.

we are being asking to solve for l.

P=2w+2l

First step: Isolate term that contains the l, so get 2l by itself first.

We are going to subtract 2w on both sides giving us:

P-2w=2l

2l=P-2w

Now that we have 2l by itself it is time to perform the last step in getting l by itself.

Second step: Divide both sides by 2.

This gives us:

l=(P-2w)/2

You may separate the fraction like so:

$l=\frac{P-2w}{2}=\frac{P}{2}-\frac{2w}{2}=\frac{P}{2}-w$ .

I don't know your options but I have solve for l in terms of P and w

and got $l=\frac{P}{2}-w$ .

Please let me know if you have further questions with this problem.

4 0

3 years ago

The question is in the picture

GrogVix [38]

Ten-thousand AFAFANDIUAHDIUAHIUDHAIDh (had to write 20 more "letters")

8 0

3 years ago

The line of reflection will (always, sometimes, never) be the perpendicular bisector between a preimage and it’s reflected image

frez [133]

Answer:

Step-by-step explanation:

line of reflection: <em>a fixed line directly in the middle of the pre-image and the reflected image. </em>

perpendicular: <em>two lines meeting at a 90 degree angle</em>

bisector: <em>line that divides something into two equal parts</em>

pre-image: <em>the original figure before any transformation or translation has been made</em>

reflected image: <em>the original image after being reflected across the line of reflection.</em>

<em />

Is the line of reflection a line running perpendicular, directly in the middle of the pre-image and the reflected image? Yes, always would be my answer.

6 0

4 years ago

The line on the graph passes through the points A (0, 6) and B (3, 0).

Natali5045456 [20]

The equation for the line passing through point A and perpendicular to AB will be y-0.5x=6, the gradient of line AB is -2, and the gradient of a line perpendicular to AB is 0.5.

<h3 /><h3>What is the slope or gradient?</h3>

A numerical assessment of a line's angle relative to the ground is known as the slope.

Given data;

m₁ is the slope of line AB

m₂ is the slope of a line perpendicular to AB

The coordinate points are,

A,(x₁,y₁)= (0, 6)

B,(x₂,y₂)=(3, 0).

The gradient of line AB;

$\rm m_{{1} }= \frac{y_2-y_1}{x_2-x_1} \\\\ \rm m_{{1} }= \frac{0-6}{3-0} \\\\ m_{{1} }=-2$

The slope of the lines has a perpendicular relation is -1;

m₁ × m₂ = -1

(-2) × m₂ = -1

m₂ = 1/2

m₂ = 0.5

The equation of the line passing through point A and perpendicular to AB;

(y - y₁) = m₂(x-x₁)

(y-6)=0.5(x-0)

y-6 = 0.5 x

y-0.5x=6

Hence, the gradient of line AB, the gradient of a line perpendicular to AB, and the equation of the line passing through point A and perpendicular to AB will be -2,0.5 and y-0.5x=6.

To learn more about the slope, refer to the link;

brainly.com/question/3605446

#SPJ1

4 0

2 years ago

What’s the nearest hundredth of 1.5757

OlgaM077 [116]

Answer: 1.58

Step-by-step explanation: 1.5757 the first 7 is the hundreth place so you round it up or down depending on whichever is closest

7 0

3 years ago

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