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docker41 [41]
2 years ago
6

Can someone help me please

Mathematics
1 answer:
STatiana [176]2 years ago
7 0
A is the correct answer
You might be interested in
If 588 digits were used to number the pages of a book how many pages are in this book.
iVinArrow [24]

Answer: 232 pages

Step-by-step explanation:

Total digits = 588

1 digit page number:

1 to 9 = 1 × 9 = 9

Number of pages = 9/1 = 9

2 - digit page number :

10 - 99 = 2 × 90 = 180

Number of pages = 180/2 = 90

3 - digit page number :

588 - (9 + 180) = 588 - 189 = 399

Number of pages with 3 - digits = 399/3 = 133

Therefore, the total number of pages the book has is :

(9 + 90 + 133) = 232 pages

6 0
2 years ago
Eight people are equally sharing 12 muffins. How many muffins will each person receive?
Marina CMI [18]
Total number of muffins = 12 muffins
Total number of people sharing muffin = 8

Muffins each person will receive = Total number of muffins
                                                          ---------------------------------
                                                          People sharing muffins
                                                   
                                                    = 12/8
                                                    = 1 1/2  OR  1.5 muffins



7 0
2 years ago
Read 2 more answers
Bob’a last delivery from Conco oil Company was $125.32. A total of 80.5 gallons was delivered. What was the price per gallon to
julia-pushkina [17]

Answer:

$1.56

Step-by-step explanation:

125.32 : 80.5 = 1.55677 => ~1.56$

5 0
2 years ago
Mr. Chen is painting one wall of a room in his attic. He needs to detemine the area of the wall so he will know how much paint h
MAVERICK [17]

Area of the figure

= (area of rectangle) + (area of triangle)

= (8 × 10) + (½ × 4 × 8)

= 80 + 16

= 96

Area = 96ft²

Quarts of paint needed

= 96/22

= 48/11

= 4.36

Mr. Chen will have to buy 5 quarts of paint.

8 0
2 years ago
Please someone help me to prove this..​
Pachacha [2.7K]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Sum to Product Identities:

\sin x+\sin y=2\sin \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\sin x-\sin y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=-2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \qquad \dfrac{\sin 5-\sin 15+\sin 25 - \sin 35}{\cos 5-\cos 15- \cos 25 + \cos 35}

\text{Reqroup:}\qquad \qquad \qquad \dfrac{(\sin 25+\sin 5)-(\sin 35 + \sin 15)}{(\cos 35+\cos 5)-(\cos 25 + \cos 15)}

\text{Sum to Product:}\quad \dfrac{2\sin \bigg(\dfrac{25+5}{2}\bigg)\cos \bigg(\dfrac{25-5}{2}\bigg)-2\sin \bigg(\dfrac{35+15}{2}\bigg)\cos \bigg(\dfrac{35-15}{2}\bigg)}{2\cos \bigg(\dfrac{25+15}{2}\bigg)\cos \bigg(\dfrac{25-15}{2}\bigg)-2\cos \bigg(\dfrac{35+5}{2}\bigg)\cos \bigg(\dfrac{35-5}{2}\bigg)}\text{Simplify:}\qquad \qquad \dfrac{2\sin 15\cos 10-2\sin 25\cos 10}{2\cos 20\cos 15-2\cos 20\cos 5}

\text{Factor:}\qquad \qquad \dfrac{2\cos 10(\sin 15-\sin 25)}{2\cos 20(\cos 15-\cos 5)}

\text{Sum to Product:}\qquad \dfrac{\cos 10\bigg[2\cos \bigg(\dfrac{15+25}{2}\bigg)\sin \bigg(\dfrac{15-25}{2}\bigg)\bigg]}{\cos 20\bigg[-2\sin \bigg(\dfrac{15+5}{2}\bigg)\sin \bigg(\dfrac{15-5}{2}\bigg)\bigg]}

\text{Simplify:}\qquad \qquad \dfrac{\cos 10[2\cos 20\sin (-5)]}{\cos 20[-2\sin 10\sin 5]}\\\\\\.\qquad \qquad \qquad =\dfrac{-2\cos10 \cos 20 \sin 5}{-2\sin 10 \cos 20 \sin 5}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 10}{\sin 10}\\\\\\.\qquad \qquad \qquad =\cot 10

LHS = RHS:  cot 10 = cot 10   \checkmark

8 0
2 years ago
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