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7nadin3 [17]
3 years ago
7

qual a concentração de uma solução contendo 50g de cloreto de sódio dissolvidos em 250ml de solução​

Chemistry
1 answer:
anygoal [31]3 years ago
6 0

Answer:

200 g/L

Explanation:

The concentration of a solution (also called molarity) can be calculated with the formula:

M=\frac{m}{V}

where

m is the mass of the solute

V is the volume of the solution

For the solution in this problem we have:

m = 50g is the mass of the solute

V = 250 mL = 0.250 L is the volume of the solution

Therefore, the concentration of the solution is:

M=\frac{50 g}{0.250 L}=200 g/L

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Sodium hydroxide (a base) reacts with hydrochloric acid. After the reaction is complete, a pH indicator is added to the solution
fomenos

Answer:

hydrochloric acid

Explanation:

The hydrochloric acid in this reaction is the limiting reactant. A limiting reactant is the reactant that is used up in a chemical reaction. It determines the extent of the reaction.

Since the solution indicates a basic one after the end of the reaction, this suggests that more of the sodium hydroxide is still left unreacted with.

The reactant in excess supply here is the sodium hydroxide and the bulk of it is till left in solution.

7 0
3 years ago
ASAP HELP
dlinn [17]

One molecule of sucrose is burned with oxygen to make carbon dioxide and water.

Disaccharide sugar sucrose is composed of glucose and fructose. It is produced naturally by plants and is the main component of white sugar. C₁₂H₂₂O₁₁ is the chemical formula for it.

Extraction and refining sucrose for human use can be done from either sugarcane or sugar beet. Raw sugar is created from crushing the cane, which is consistently delivered to other sectors to be refined into pure sucrose. Sugar mills generally are located in the tropical regions near the sugarcane plantations.

<em>                    C₁₂H₂₂O₁₁ + 12O₂  →  12CO₂ + 11H₂O</em>

When one molecule of sucrose is burnt, we get 12 carbon dioxide molecules.

To learn more about sucrose,

brainly.com/question/978083

#SPJ1

3 0
1 year ago
What will you observe when you open a bottle of concentrated hydrochloric acid?
Soloha48 [4]

Answer:

Strong affinity of HCl gas for moisture in air results in forming of droplets of liquid solution which appears like a cloudy smoke.

Explanation:

#followformore

Hope this helps :)

7 0
3 years ago
What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?
My name is Ann [436]

Answer:

  • 602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The<em> yield</em> is measured by the amount of each product produced by the reaction.

The chemical formula of <em>fluorene</em> is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The <em>oxidation</em>, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

        2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O

To calculate the yield follow these steps:

<u>1. Mole ratio</u>

          2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O

<u />

<u>2. Convert 175mg of fluorene to number of moles</u>

  • 175mg/times 1g/1,000mg=0.175g

  • Number of moles = mass in grams / molar mass

  • \text{number of moles}=0.175g/166.223g/mol=0.0010528mol

<u>3. Set a proportion for each product of the reaction</u>

a) <u>For CO₂</u>

i) number of moles

         2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x

x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

  • mass = number of moles × molar mass
  • mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) <u>For H₂O</u>

i) number of moles

0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

  • mass = number of moles × molar mass
  • mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg
4 0
3 years ago
A 0.0100 M solution of AgNO3 has a concentration of Ag ion equivalent to
qaws [65]

Answer:

0.0100M of AgNO3 contains 0.0100M of Ag+

Explanation:

AgNO3 when ionized yields Ag+ and NO3-. This means that the amount of AgNO3 in solution is equivalent to the amount of Ag+ and NO3- in that same solution.

1M of AgNO3 solution produces 1M of Ag+  

1M of AgNO3 solution produces 1M of NO3-

This occurs because of the complete ionization of AgNO3 in solution, allowing complete dissolution of the compound.

6 0
3 years ago
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