Answer:
[H_3 O^+] = 1.0 ×10^-13
Explanation:
If we multiply the left side we get, 1e - 13. We add 13 to the right side while subtracting the remaining value from the left side (H3O+) than combine like terms. As you will get pH = 13.00
Answer:
C: The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts
Explanation:
Looking at the options, the correct one is Option C because the actual yield usually depends on the conditions of the reaction, while the theoretical yield usually varies with only the amount of reactant.
Answer:
0.56 liters
Explanation:
First we <u>convert 0.80 grams of O₂ into moles</u>, using its molar mass:
- 0.80 g ÷ 32 g/mol = 0.025 mol
At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we <u>calculate the volume that 0.025 moles of O₂ gas would occupy</u>:
- 0.025 mol * 22.4 L/mol = 0.56 L
Thus the answer is 0.56 liters.
The chemical reaction would be as follows:
<span>2Na + S → Na2S
We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:
45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S
The limiting reactant would be Na. We calculate as follows:
1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced</span>
