Answer:
moles B = 2.32 moles
Explanation:
In this case, we can assume that both gases are ideals, so we can use the expression for an ideal gas which is:
PV = nRT
From here, we can calculate the total moles (n) that are in the container, and then, by difference, we can calculate how much we have of gas B.
For this case, we will use R = 0.082 L atm / mol K. Solving for n:
n = PV/RT
n = 5 * 20 / 0.082 * 303
n = 4.02 moles
If we have 4.02 moles between the two gases, and we have 1.70 from gas A, then from gas B we simply have:
Total moles = moles A + moles B
moles B = Total moles - moles A
moles B = 4.02 - 1.70
moles B = 2.32 moles
We have 2.32 moles of gas B
Answer:
According to Thompson's model, Every atom consists of a positively charged sphere of radius 10-- 10m in which entire mass and positive charge of the atom are uniformly distributed inside the sphere electrons are embedded like seeds in watermelon. According Rutherford entire poistive charge and mass of the atom are concentrated in a tiny central core of the atom which is called atomic nucleus contains. Size of nucleus = 10-- 15m. The nucleus contains protons and neutrons. Negatively charged electrons revolve around the nucleus in circular orbits.
Explanation:
<span>magnesium oxide is a compound that is composed of one atom of magnesium and two atoms of oxygen. The compound is a combination of Mg2+ ion and O2-. The ions translate into atoms which reflects on the subscripst of the elements already. magnesium oxide is a basic oxide with the pH level greater than 7.</span>
What are your examples to work off?
Answer:
13g
Explanation:
34+10+26=70
70-57=13
13g would complete the equation
