The margin of error for a sample proportion is given by

where:

is the z score associated with the confidence level, p is the sample prortion and n is the sample size.
We assume a confidence level of 95%, then
p = 52% = 0.52 and n = 2251
Therefore, margin of error =

The the interval that is likely to contain the true population proportion is between 49.9% and 54.1%.
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The answer to your question is A. 359.5
U didn’t give us enough info. We need the radius and then we can find the volume