The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...
<u><em>Explanation</em></u>
Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2
The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners ![=^1^5C_{5} =3003](https://tex.z-dn.net/?f=%3D%5E1%5E5C_%7B5%7D%20%3D3003%20)
For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.
So, the possible ways for selecting 2 pasta dinners ![=^7C_{2}*^8C_{3} =1176](https://tex.z-dn.net/?f=%3D%5E7C_%7B2%7D%2A%5E8C_%7B3%7D%20%3D1176)
The possible ways for selecting 3 pasta dinners ![=^7C_{3}*^8C_{2} =980](https://tex.z-dn.net/?f=%3D%5E7C_%7B3%7D%2A%5E8C_%7B2%7D%20%3D980)
The possible ways for selecting 4 pasta dinners ![=^7C_{4}*^8C_{1} =280](https://tex.z-dn.net/?f=%3D%5E7C_%7B4%7D%2A%5E8C_%7B1%7D%20%3D280)
The possible ways for selecting 5 pasta dinners ![=^7C_{5}*^8C_{0} =21](https://tex.z-dn.net/?f=%3D%5E7C_%7B5%7D%2A%5E8C_%7B0%7D%20%3D21)
Thus, the probability for selecting at least 2 pasta dinners ![=\frac{1176+980+280+21}{3003} =\frac{2457}{3003} =0.8181.....](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1176%2B980%2B280%2B21%7D%7B3003%7D%20%3D%5Cfrac%7B2457%7D%7B3003%7D%20%3D0.8181.....)
Answer:35975353532 is your answer hope this helped
Step-by-step explanation:
pleas make brainly
Break into 2 seperate shapes:
top section: 5 * 5 * 5 = 125
lower part" 5 * 20 * 5 = 500
500 + 125 = 625
answer is A
Answer:
133 bucks can i get brainliest
Step-by-step explanation: