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3 years ago

If two sides of a triangle have lengths 18 cm and 13 cm the third side must be greater then what and less then what

Mathematics

1 answer:

maw [93]3 years ago

7 0

If you multiple 13 18=234 then subtract that by 13 18 203 that would be the area so 13 is less than 18

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I NEED HELP WITH MATH

LuckyWell [14K]

Answer:

B and D

Step-by-step explanation:

When you subtract a negative number, you are adding.

7-(-7)=7+7=14

Adding goes right on a number line.

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2 years ago

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A robot can complete 3 tasks in hour. Each task takes the same amount of time. 10 a. How long does it take the robot to complete

maksim [4K]

Answer:

a.20 minutes

b.3 tasks

Step-by-step explanation:

60 divided by 3 = 20

7 0

3 years ago

Please help I’ll mark you as brainliest if correct

Alecsey [184]

Answer:

153.94 is your answer.

Step-by-step explanation:

I believe it would be the last one, but let me explain. So to find the area of a circle with just the diameter, the formula would be 1 /4 π d2. Which is one fourth times pie, multiplied with the diameter to the second power. So if we put 14 in the equation would look like this 1/4*π*14*2. So if we use this formula, we get 153.94. Or something close to that. I hope this helps! Good luck!! ;)

7 0

3 years ago

Please solve the equation _4(4n+2)=4

MrRissso [65]

16n+8=4
16n=4-8
16n=-4
n=-4/16
n=-1/4.

8 0

3 years ago

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What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago