Answer:
the height after 2 seconds will be 128 feet
Step-by-step explanation:
Data provided in the question:
Initial velocity = 96 feet per second
The function of height of falling debris above the ground is given as:
h(t) = 96t - 16t²
A) To find height after time t = 2 seconds
substituting the value of time in the above function, we get
h(t) = 96 × 2 - 16 × 2²
or
h(t) = 192 - 16 × 4
or
h(t) = 192 - 64
or
h(t) = 128 feet
Hence,
the height after 2 seconds will be 128 feet
3/16= 0.1875
Though if you mean 16/3 it is 5.333.....
<span>2x-1/4(12x+4)=3
</span>⇒ 2x -1/4*(12x) -1/4*4= 3 (distributive property)
⇒ 2x -3x -1= 3
⇒ -x= 3+1
⇒ -x= 4
⇒ x= -4
<span>
Final answer: x=-4~
</span>
3/5 - 2/5 = 1/5
I hope that helps!
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