3 years ago

Find the slope of a line containing 4,-6 and 6,-4

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

The slope of the problem is (1,1)

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What is the 7th term of the geometric sequence where a1 = -625 and a2 = 125

kykrilka [37]

Since the sequence is geometric, there is some constant $r$ such that the sequence is recursively given by

$a_n=ra_{n-1}$

By this definition, you can recursively substitute into the right hand side the definition for $a_{n-1},a_{n-2},\ldots$ to find an explicit formula for the $n$ th term.

$a_n=ra_{n-1}=r^2a_{n-2}=r^3a_{n-3}=\cdots=r^{n-1}a_1=-625r^{n-1}$

You know the second term, which means you can find $r$ :

$a_2=-625r^{2-1}\implies125=-625r\implies r=-\dfrac15$

So, the 7th term of the sequence is

$a_7=-625\left(-\dfrac15\right)^{7-1}=-\dfrac1{25}$

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3 years ago

Choose the point-slope form of the equation below that represents the line that passes through the points (-6, 4) and (2, 0).

Arte-miy333 [17]

Point slope form
y-y1=m(x-x1)
slope=m
a point is (x1,y1)

slope=(y2-y1)/(x2-x1)
given
(-6,4) and (2,0)
slope=(0-4)/(2-(-6))=-4/(2+6)=-4/8=-1/2

a point is (-6,4)
x1=-6
y1=4

y-4=-1/2(x+6)
not listed

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Consider the line y=- 2x+7.

iVinArrow [24]

Answer:

the slope is rhe same -2

Step-by-step explanation:

the slope is the opposite +1/2

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I hope this helps you :)

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