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guajiro [1.7K]
3 years ago
9

Find the slope of a line containing 4,-6 and 6,-4

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
7 0
The slope of the problem is (1,1)
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Solve for x<br><br> A 130<br> B 120<br> C 23<br> D 70
34kurt

Answer:

B)120º

Step-by-step explanation:

70+50=x

120=x

7 0
3 years ago
The students in Mr. Wilson's Physics class are making golf ball catapults. The
Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is 0 \leq x \leq 48.6\ ft and the range is 0 \leq y \leq 8.3\ ft

Step-by-step explanation:

we have

y=-0.014x^{2} +0.68x

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's  distance from the catapult in feet

y is the flight of the balls in feet

Part a)  How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-0.014x^{2} +0.68x=0

so

a=-0.014\\b=0.68\\c=0

substitute in the formula

x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}

x=\frac{-0.68(+/-)0.68} {(-0.028)}

x=\frac{-0.68(+)0.68} {(-0.028)}=0

x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

y=-0.014x^{2} +0.68x

Find out the derivative and equate to zero

0=-0.028x +0.68

Solve for x

0.028x=0.68

x=24.3

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint  between the x-intercepts

x=(0+48.6)/2=24.3\ ft

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

y=-0.014(24.3)^{2} +0.68(24.3)

y=8.3\ ft

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A  reasonable domain is the distance between the two x-intercepts

so

0 \leq x \leq 48.6\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A  reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

so

we have the interval -----> [0,8.3]

0 \leq y \leq 8.3\ ft

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0
3 years ago
If you have 2 millionaire dollars and 5 Million and you give your whole family how much is that.
Andrej [43]

So it depend's how much if you have 2million dollars and 5million dollars you have 7 million dollars.

So if you have 7 family member divde 7 million by 7 then you'll get 1 million so everyone get's 1 million

6 0
3 years ago
Read 2 more answers
Erite 2 • 2•2 •2• 2 • 3•3•3• 3 in exponential form?
Delicious77 [7]

Answer:

2^5 * 3^4

a

a

a

a

a

a

a

a

a

aa

7 0
4 years ago
How many solutions does y=3/4x+2 and y=-3/4x+5 have?
Reptile [31]

Answer:

Only one solution

x=1/2

Step-by-step explanation:

Collect like terms.

3/2x=3

Solve for x.

6x=3

x=1/2

5 0
4 years ago
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