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arlik [135]
3 years ago
11

A ball is dropped from a height of 1 metre. If it reaches 0.7 times the height of the height of the previous bounce at each boun

ce, work out how many times the ball bounces until the height is less than 1 centimetre
Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0
Hello,
Let's  n the number of the bounce

u_{0} =100\\
 u_{1} =0.7*100\\
 u_{2} =0.7^{2}*100\\
 u_{3} =0.7^{3}*100\\
...
 u_{n} =0.7^{n} *100\\
 
u_{n} =0.7^{n}*100 \leq \ 1\\




ln(0.7^n)+ln(100) <=ln(1)
==>n*ln(0.7) <=-ln(100)
==>n >=-ln(100)/ln(0.7)
==> n>=12,911392471625765979506986280561

The ball bounces 12 times until the height is less than 1 centimetre .

If you don't like my calculus see the file joined.



Download xls
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Step-by-step explanation:

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Step-by-step explanation:

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Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.

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