Well, if it starts on 11:00 am, add 4 hours = 3:00 + 5 min = end time = 3:05 am.
Hopes this helps ;)
Answer:
first we find the common difference.....do this by subtracting the first term from the second term. (9 - 3 = 6)...so basically, ur adding 6 to every number to find the next number.
we will be using 2 formulas....first, we need to find the 34th term (because we need this term for the sum formula)
an = a1 + (n-1) * d
n = the term we want to find = 34
a1 = first term = 3
d = common difference = 6
now we sub
a34 = 3 + (34-1) * 6
a34 = 3 + (33 * 6)
a34 = 3 + 198
a34 = 201
now we use the sum formula
Sn = (n (a1 + an)) / 2
S34 = (34(3 + 201))/2
s34 = (34(204)) / 2
s34 = 6936/2
s34 = 3468 <=== the sum of the first 34 terms:
Answer: 3x^3 - 3x^2 - 4x - 4
Explanation:
(x - 2)(3x^2 + 3x + 2)
= x(3x^2 + 3x + 2) - 2(3x^2 + 3x + 2)
= 3x^3 + 3x^2 + 2x - 6x^2 - 6x - 4
= 3x^3 - 3x^2 - 4x - 4
