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Mama L [17]
3 years ago
14

Amy deposits \$500 into an account that pays simple interest at a rate of 5% per year . How much interest will she be paid in th

e first 2 years?
Mathematics
2 answers:
Eddi Din [679]3 years ago
7 0

Answer:

$50

Step-by-step explanation:

pnr/100

500×5×2/100

$50

snow_tiger [21]3 years ago
7 0

Answer:

$50

Step-by-step explanation:

The formula for simple interest is: A=Prt/100

P=500

r=5

t=2

So, once you input the values it will be: A=500 x 5 x 2/100

   And thus your answer will be $50

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Answer: 25

Assuming the dotted line touches the middle of the base of the triangle,

Using Pythagoras Theorem,

(30/2)^2 + (20)^2 = x^2

x^2 = (15)^2 + 400

x^2 = 625

x = √625 or -(√625)

x = 25 or -25

But since x needs to be a positive value,

x = 25

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4 years ago
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Which of these are the intercepts of y = 2x − 6?
harina [27]

Answer:

B. (3, 0), (0, -6)

Step-by-step explanation:

Plug 0 in for each variable one at a time, and you will get both intercepts.

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3 years ago
What is 196.7 16 in simplest form?
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70 divided by 14
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3 years ago
the equation shows the radius of the algae,f(d), in mm,after d days: f(d)=7(1.06)^d the radius of the algae was approximately 13
Andrei [34K]

Answer:

\begin{gathered} A)\text{ }Domain:\text{ \lparen0,11\rparen} \\ B)\text{ the y-intercept represents that in 0 days the diameter of the algae will be 7 mm.} \\ C)\text{ rate of change= 0.64. This means that on average the algae grows 0.64mm per day.} \end{gathered}

Step-by-step explanation:

If the radius of the algae was approximately 13.29 mm, substitute f(d)=13.29 and solve for d to determine the domain:

\begin{gathered} 13.29=7\left(1.06\right)^d \\ \frac{13.29}{7}=1.06^d \\ d=\frac{\text{ log\lparen13.29/7\rparen}}{\text{ log\lparen1.06\rparen}} \\ d=11 \\ \text{ Then, the domain:} \\ (0,11) \end{gathered}

B. The y-intercept is obtained when d=0, hence;

\begin{gathered} d=0 \\ f(0)=7(1.06)^0 \\ f(0)=7 \end{gathered}

Therefore, the y-intercept represents that in 0 days the diameter of the algae will be 7 mm.

C. Now, to determine the rate of change of a function, use the following equation:

\text{ rate of change=}\frac{change\text{ over y}}{change\text{ over x}}

Then, determine the value of f(4):

\begin{gathered} f(4)=7(1.06)^4 \\ f(4)=8.83 \end{gathered}

Hence, the rate of change on that interval of the function:

\begin{gathered} \text{ rate of change=}\frac{13.29-8.83}{11-4} \\ \text{ rate of change=0.64 } \end{gathered}

This means that on average the algae grows 0.64mm per day.

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