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3 years ago

PLEASE HELPPP!!!!

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

Answer:

A. The point (0,0) shows that the cost is $0 for 0 kg of cashews.

C. The point (2,60) shows that it cost $60 for 2 kg of cashews.

B. The constant of proportionality for this graph is 30.

Step-by-step explanation:

D is wrong

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camelback mountain has an elevation change of 1,264 feet. how many pennies would it take to make a stack that high? pls show all

tatiyna

1 penny = 0.005 ft
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8 0

2 years ago

Simplify by combining like terms -17+2(6x-1)+5

earnstyle [38]

$\huge\boxed{12x-14}$

Start with the original expression.

$-17+2(6x-1)+5$

Use the Distributive Property — multiply $2$ by both $6x$ and $-1$ .

$-17+12x-2+5$

Combine the like terms — add up all the constants.

$-14+12x$

Reorder the terms.

$\large\boxed{12x-14}$

5 0

3 years ago

Read 2 more answers

A triangle whose angles have measures x x+5 and x+10

nirvana33 [79]

the correct question is
A triangle whose angles have measures x x+5 and x+10.How do you find the measure of each angle?

we know that
The Sum of internal angles of any triangle = 180∘
so
[x+(x+5)+(x+10)]=180---------------> 3x+15=180----------> 3x=165-------> x=55°

the answer is
the measure of each angle is
x=55°
x+5=60°
x+10=65°

4 0

4 years ago

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

4 years ago

I need help!!!! Which represents the inverse of the function f(x)=4x?

Mrac [35]

Answer:

$h(x)=\frac{1}{4}x$ .